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Alex
4 years ago
11

What are some important factors to consider when choosing a warm-up before your workout?

Physics
2 answers:
TEA [102]4 years ago
6 0

<u>Answer:</u>

Prior to exercise, a proper warm-up of 10-15 minutes is extremely important to avoid injuries.

  1. Don't go too hard in the beginning and boost your activity level slowly. A good indication of a proper warm-up is that you feel sweat on your body parts.
  2. Don't overstretch right in the beginning as it can cause sore in your muscles and joints or stress fractures.
  3. Take a break if you feel sick or fatigues and use other drinks along with water to replace electrolytes and body fluids.  
Flauer [41]4 years ago
5 0

Answer:

Remember that the objective of warming up is avoiding problems when you are working out.

So the first thing that you need to have in mind is that you need to start slow, to prevent any possible harm.

You need to warm all your body, not only some parts of it.

when stretching, do not do it as you normally do, because it will relax your muscles, you should do dynamic stretching, this means that you keep your body in a position where there is no tension, and moving your body to generate tension, then relaxing again, then generating tension, and so on.

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A slanted vector has a magnitude of 41 N and is at an angle of 23 degrees north of east. What are the magnitude and direction of
jenyasd209 [6]

Answer:

The horizontal component is 37.74 N to east

The vertical component is 16.02 N to North

Explanation:

Any slant vector has two components

→ Horizontal component = R cos Ф

→ Vertical component = R sin Ф

→ R is the magnitude of the vector

→ Ф is the direction of the vector with positive part of the horizontal axis

A slanted vector has a magnitude of 41 N and is at an angle of 23

degrees north of east

23° north of east means the angle between the vector and the

east direction is 23° (east is the positive horizontal direction)

That means R is 41 N and Ф is 23°

→ R = 41 N , Ф = 23°

→ The horizontal component = 41 × cos(23) = 37.74 N east

→ The vertical component = 41 × sin(23) = 16.02 N North

<em>The horizontal component is 37.74 N to east</em>

<em>The vertical component is 16.02 N to North</em>

7 0
4 years ago
Select whether the argument is an example of a deductive or an inductive argument:
viva [34]
The answer is a inductive
7 0
4 years ago
Help me please please?
Rainbow [258]

Answer: I looked it up and it says something about the waves traveling in a solid but I don’t know if that’s correct.

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3 years ago
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You’ve made the finals of the science Olympics. As one of your tasks you’re given 1.0 g of copper and asked to make a cylindrica
Pani-rosa [81]

Answer:

Length = 2.92 m

Diameter = 0.11 mm

Explanation:

We have m = dl D \ \ \& \ \ \ R = \frac{\rho l}{A} , where:

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m = 1.0 g = 1 \times 10^{-3} \ kg\\R = 1.3 \ \Omega\\\rho = 1.7 \times 10^{-8} \Omega m\\d = 8.96 \ g/cm^3 = 8960 kg/m^3

We divide the first equation by the second equation to get:

\frac{m}{R} = \frac{d A^2}{\rho}

A^2 = \frac{m \rho}{dR} \\\\A^2 = \frac { 1 \times 10^{-3} \times 1.7 \times 10^{-8}}{8960 \times 1.3}\\\\A^2 = 1.5 \times 10^{-15}\\\\ A= 3.8 \times 10^{-8}   \ m^2

Using this Area, we find the diameter of the wire:

D = \sqrt{\frac{4A}{\pi}}

D = \sqrt{\frac{4 \times 3.8 \times 10^{-8} }{\pi}}

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To find the length, we multiply the two equations stated initially:

mR = d\rho l^2\\\\l^2 = \frac{mR}{d\rho} \\\l^2 = \frac {1.0 \times 10^{-3} \times 1.3}{8960 \times 1.7\times 10^{-8}}

l^2 = 8.534\\l =   2.92 \ m

8 0
3 years ago
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Answer:

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Utilize Existing Green Space Connections

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