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viva [34]
2 years ago
13

Angel hits a ball with a ball. The action is the ball . What what is reaction force?

Physics
1 answer:
Mumz [18]2 years ago
5 0

When Angel hits a ball with the ball. As the action is a ball as it is hitted. The reaction force is the force exerted on another ball.

Newton’s third law of motion describes the two forces, action and reaction forces. This states that for every action force, there is an equal and opposite reaction force.

As Angel hits a ball with another ball, the action is the ball as it is hit. The ball exerts a force on the ball. This is the action force. The ball exerts an equal and opposite force on the bat, which is known as the reaction force.

Learn more about Newton's Law of motion:

brainly.com/question/10454047

#SPJ10

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A small metal sphere weighs 0.34 N in air and has a volume of 13 cm3 . What is the acceleration of the sphere as it falls throug
Xelga [282]

To solve this problem we will apply the concepts related to the balance of forces. Said balance will be given between buoyancy force and weight, both described as derived from Newton's second law, are given as

Buoyancy force

F_B = V\rho g

Here,

V = Volume

\rho=Density of air

g = Acceleration due to gravity

Weight

F_W = mg

m = mass

g = Gravity

Our values are given as,

\text{Weight of the sphere} = W = 0.34 N

\text{Volume} = V = 13 cm^3 = 13*10^{-6}m^3

\text{density of air} =\rho =1.29kg/m^3

\text{gravity}= g = 9.8 m/s^2

Then,

F = V\rho g

Replacing,

F = (13*10^{-6}m^3 )(1.29Kg/m^3)( 9.8 m/s^2) = 1.6434* 10^{-4} N

Now net force is ,

F_{net} = mg - F

Mass of the sphere is

m = \frac{W}{g} = \frac{0.34N}{9.8m/s^2} = 0.03469 kg

Now acceleration of the sphere is

a = \frac{F_{net}}{m}

a = \frac{( 0.34 N)- (1.6434* 10^{-4} N)}{0.03469 kg}

a = 9.822m/s^2

Therefore the acceleration of the sphere as it falls through water is 9.822m/s^2

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Explanation:

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Oksanka [162]

Answer:

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Explanation:

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