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Anna [14]
3 years ago
15

As the launch force increase the launch velocity will

Physics
1 answer:
FrozenT [24]3 years ago
5 0

Answer:

As the launch force increase the launch velocity will

<em><u>Increase</u></em>

The reason for your answer to number six is because

<em><u>There is a direct relationship between force and acceleration.</u></em>

<em><u /></em>

Explanation:

<em>It is known all over the place that, there is a direct relationship between Force and acceleration of an object leading to an increase in force being directly proportional to the increase in the acceleration of the given object and vice versa.</em>

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A charge of 8.0 pc is distributed uniformly on a spherical surface (radius = 2.0 cm), and a second charge of â3.0 pc is distribu
loris [4]
According to Gauss' law, the electric field outside a spherical surface uniformly charged is equal to the electric field if the whole charge were concentrated at the center of the sphere.

Therefore, when you are outside two spheres, the electric field will be the overlapping of the two electric fields:
E(r > r₂ > r₁) = k · q₁/r² + k  · q₂/r² = k · (q₁ + q₂) / r²
where:
k = 9×10⁹ N·m²/C²

We have to transform our data into the correct units of measurement:
q₁ = 8.0 pC = 8.0×10⁻¹² C
q₂ = 3.0 pC = 3.0×10<span>⁻¹² C
</span><span>r = 5.0 cm = 0.05 m

Now, we can apply the formula:
</span><span>E(r) = k · (q₁ + q₂) / r²
      = </span>9×10⁹ · (8.0×10⁻¹² + 3.0×10⁻¹²) / (0.05)²
      = 39.6 N/C

Hence, <span>the magnitude of the electric field 5.0 cm from the center of the two surfaces is E = 39.6 N/C</span>
4 0
4 years ago
A 400g mass object at rest is acted on by a 200 N net force for 12 seconds. What is it’s final velocity?
Kisachek [45]

Explanation:

do we can say that the first step is finding the acceleration of the object. We do so by saying F = ma

so a = F/m

a = 500 m/s^2

we now have the time, acceleration and initial velocity.

so we can find the final velocity by using one of newtons equations which is: vf = vi + at

so:

vf = 0 + 500 × 12

vf = 6000

note that our initial velocity was zero since the object was initially at rest.

if you still have any doubt dont hesitate to ask for further help.

3 0
2 years ago
A piece of Nichrome wire has a radius of 7.1 x 10-4 m. It is used in a laboratory to make a heater that dissipates 3.20×102 W of
bekas [8.4K]

Answer:

the length of the Nichrome wire is <em>59.88 m</em>

<em></em>

Explanation:

The resistance of a wire is determined by:

P = V² / R                              or    R = V² / P

where

  • V is the voltage
  • R is the resistance
  • P is the power

We also know that

R = PL / A

where

  • A is the area and it is equal to πr²
  • P = 3.20 × 10² W

Therefore, the length of the Nichrome wire is

L  = RA / ρ

L = (V²/P)(πr²) / ρ

L = V²πr² /  ρ P

L = (110 V)²(π)(7.1 × 10⁻⁴ m)² / (3.2 × 10² W)(100 × 10⁻⁸ Ω·m)

<em>L = 59.88 m</em>

7 0
4 years ago
A bottle of soda always has a space between the cape and the top of the liquid. Explain<br>​
serious [3.7K]

Answer:

All soft drinks contain water. When soft drink bottles are chilled in sub-zero temperatures, the water on account of its anomalous expansion expands. Thus, to provide space for expanding water, soft drink bottles are not completely filled as otherwise they will burst.

Explanation:

6 0
3 years ago
Read 2 more answers
A mass m = 0.6 kg is released from rest at the top edge of a hemispherical bowl with radius = 1.1 meters. The mass then slides w
Aneli [31]

Answer:

The  angle is  \theta   = 36.24 ^o

Explanation:

From the question we are told that

    The  mass is  m  =  0.6 \ kg

     The radius is  r =  1.1 \ m

     The speed is  v =  3.57 \ m /s

According to  the law of energy conservation

  The  potential energy of the mass at the top is equal to the kinetic energy at the bottom i.e

      m * g  *  h  =  \frac{1}{2}  *  m * v^2

 =>    h  =  \frac{1}{2 g } *  v^2

Here h is the vertical distance traveled by the mass  which is also mathematically represented as

      h  =  r * sin (\theta )

So

     \theta   = sin ^{-1} [ \frac{1}{2* g* r } *  v^2]

substituting values

     \theta   = sin ^{-1} [ \frac{1}{2* 9.8* 1.1 } *  (3.57)^2]

     \theta   = 36.24 ^o

3 0
4 years ago
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