Jennifer, who has a mass of 50.0 kg, is riding at 35.0 m/s in her red sports car when she must suddenly slam on the brakes to av
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Answer:
Kinetic energy of diver at 90% of the distance to the water is 9000 J
Explanation:
Let d is the distance between the position of the diver and surface of the pool.
Initially, the diver is at rest and only have potential energy which is equal to 10000 J.
As the diver dives towards the pool, its potential energy is converting into kinetic energy due to law of conservation of energy, as total energy of the system remains same.
Energy before diving = Energy during diving
(Potential Energy + Kinetic Energy) = (Kinetic Energy + Potential Energy)
When the diver reaches 90% of the distance to the water, its kinetic energy
is 90% to its initial potential energy, as its initial kinetic is zero,i.e.,
K.E. =
K.E. = 9000 J
Answer:
The boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
Explanation:
Given the data in the question;
Using the Clapeyron equation
where is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu
T is the temperature ( 15 + 460 )R
m is the mass of water ( 0.5 Ibm )
is specific volume ( 1.5 ft³ )
we substitute
/
272.98 Ibf-ft²/R
Now,
where P₁ is the initial pressure ( 50 psia )
P₂ is the final pressure ( 60 psia )
T₁ is the initial temperature ( 15 + 460 )R
T₂ is the final temperature = ?
we substitute;
480.275 R
Therefore, boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
Answer:
a) F₁ = 1.48 x 10³ N
b) P = 1.88*10⁵ Pa
c) The work is equal in both pistons
Explanation:
Pascal´s Principle can be applied in the hydraulic press:
If we apply a small force (F₁) on a small area piston (A₁), then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F₂) can be exerted that is proportional to the area(A₂) of the piston.
Pressure is defined as the force per unit area:
Formula (1)
P₁=P₂
Formula (2)
Data
r₁= 5 cm = 0.05 m
r₂= 15 cm = 0.15 m
F₂= 13300N
Area of the pistons (A₁,A₂)
A=π*r² : Area of the circle
A₁ = π*(0.05)²=7.85*10⁻³ m²
A₂= π*(0.15)²= 70.69*10⁻³ m²
a) Force that compressed air must exert to lift a car weighing 13300 N
We replace data in the formula (2)
F₁ = 1.48 x 10³ N
b) Air pressure produced by F₁
We replace data in the formula (1)
F₁ = 1.48 x 10³ N , A₁ = 7.85*10⁻³ m²
P= 1.88*10⁵ Pa
c)The volume of liquid displaced by the small piston is distributed in a thin layer on the large piston, so that the product of the force by the displacement (the work) is equal in both pistons.