Answer:
The ratio is 
Explanation:
The diagram for this question is shown on the first uploaded image
Here we are assume the acceleration of the train is a
which makes the acceleration of each car a
From the question we are told that
Considering the second car
The force causing it s movement is mathematically represented as

Considering the first car
The force causing it s movement is mathematically represented as

=> 
=> 
=> 
=> 
Answer:
0.2885 m/s²
Explanation:
The formula for centripetal acceleration is given as;

Given that;
speed = v = 1.5m/s
radius = r = 7.8

Hey, Name's Jessy. I hope, I answer your question.
Nearly 400 lbs,by 11.73%.
Answer:
101397.16 pa
Explanation:
The pressure recorded will be equal to pgh
Where p = density of mercury = 13.6x10^3 kg/m^ 3
g = acceleration due to gravity 9.81 m/s^2
h = height of mercury in the column = 760 mm = 760x10^-3 m
Pressure = 13.6x10^3 x 9.81 x 760x10^-3 = 101397.16 pa
Answer:
Valence electrons
Explanation:
The valence electrons are found in the outermost shell of an atom. They are the most loosely held electrons found within an atom. These valence electrons are involved and are used to form bonds when atoms combines together.
The energy required to remove these loosely held electrons is relatively low compared to electrons located in the inner orbitals. This is why when atoms combines, they use the outermost electrons to form bonds and mimic stable atoms like those of the noble gases.