Answer:
Explanation:
Left block is on surface with higher inclination so it will go down . If T be tension
For motion of block A ,
net force = mgsin60 - (T + mg cos 60 x μ ) , μ is coefficient of friction .
ma = mgsin60 - T - mg cos 60 x .1
10a = 277.13 - T - 16
= 261.13 - T
T = 261.13 - 10a
For motion of block B
T - mg sin30 - mgcos30 x μ = ma
T- 160 - 27.71 = 10 a
261.13 - 10a - 160 - 27.71 = 10a
73.42 = 20a
a = 3.67 ft / s²
common acceleration = 3.67 ft / s²
Answer:
118kg
Explanation:
answered
Given
density of the cube= 8050 kg/m3 .
length of the sizes of the cube=24.5 cm
We can convert the length to cm for unit consistency.
It's length =24.5 cm =0.245m
✓ the length of sizes of the cube is the same, then the volume can be calculated as
Volume= L^3
= (0.245m)^3
=0.01470625 m^3
✓ but we know that
Density = mass/ volume
Then,
Mass= (Volume × density)
= (0.01470625)(8050)
= 118 kg
Hence, the mass of the cube is 118 kg
It's easy raising the barbell.
here the answer to your question hope it helps you
electric circuit
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