3 years ago

What does bidmass stant for in maths

Mathematics

2 answers:

aalyn [17]3 years ago

7 0

Bodmas= Bracket, of, division, multiplication, addition, subtraction

alex41 [277]3 years ago

3 0

Brackets, Indices, Division and Multiplication, Addition and Subtraction

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What word describes the equal shares of the shape

nexus9112 [7]

The word that describes it is congruent

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Jana finished 1/4 of her homework at school and 2/3 of it before dinner. How much of her homework has she done

Galina-37 [17]

Answer:

the answer is 11/12

Step-by-step explanation:

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3 years ago

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3 years ago

Points A, B, and C are collinear. Point B is between A and C. Solve for x if AC = 3x + 3, BC = 3, and AB = 2x + 2.

Ksenya-84 [330]

Answer:

x=2.

Step-by-step explanation:

It is given that points A, B, and C are collinear. Point B is between A and C.

Using segment addition property, we get

$AC=AB+BC$

It is given that AC = 3x + 3, BC = 3, and AB = 2x + 2.

$3x+3=(2x+2)+3$

$3x+3=2x+5$

Isolate variable terms.

$3x-2x=5-3$

$x=2$

Therefore, the value of x is 2.

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3 years ago

If √2 = 1.414 then the value of 5+√2 / 5-√2 is

Gala2k [10]

Answer:

1.787

Step-by-step explanation:

$\\ \sf \frac{5 + \sqrt{2} }{5 - \sqrt{2} } \times \frac{5 + \sqrt{2} }{5 + \sqrt{2} }$

$\\ \sf = \frac{(5 + \sqrt{2}) }{5 - \sqrt{2} } \times \frac{(5 + \sqrt{2}) }{5 + \sqrt{2} }$

$\\ \sf = \frac{25 + 5 \sqrt{2 } + 5 \sqrt{2} + 2 }{( {5})^{2} - ( \sqrt{ {2}})^{2} }$

$\\ \sf = \frac{27 + 10 \sqrt{2} }{25 - 2}$

$\\ \sf = \frac{27 - 10 \sqrt{2} }{23}$

Now putting the value of√2

$\\ \sf = \frac{27 + 10 \times 1.414}{23}$

$\\ \sf = \frac{27 + 14.14}{23}$

$\\ \sf = \frac{41.14}{23}$

$\\ \sf = 1.787$

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2 years ago