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aleksandrvk [35]

3 years ago

7

So, I’m doing a summative project for physical science and we have to come up with a title for it. I’m doing the project on Nept

unium (the element) what should the title be? I need help ASAP.

1 answer:

olasank [31]3 years ago

8 0

The first transuranic element.
OR
A radioactive actinide metal.

HOPE IT HELPS YOU '_'

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A child attempts to roll a ball up a long ramp and it slows as it goes up. If it is released at 2.5 m/s upward and accelerates d

valina [46]

Answer:

-0.7 m/s

Explanation:

Initial velocity (u)= 2.5 m/s

Acceleleration (a)= -0.8 m/s^2

Time taken (t) = 4 seconds

Hence,

v=u+at [1st Equation of motion]

v=2.5+-0.8*4

v=2.5-3.2

v=-0.7 m/s

Note that the negative sign indicates that the ball has changed direction and rolls downwards with gravity

8 0

3 years ago

I have no clue on how to do this

KatRina [158]

a)5m/s b)5

the 5 is because you add the seconds to get 8 seconds and then do the same with the distance to get 40. 40/8 = 5. speed = 5

Velocity = displacement/change in time

V = 40/8

I just realized how unorganised my math looks but I hope this is helpfull

3 0

3 years ago

How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?

Aleonysh [2.5K]

<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Given that ,

Initial Velocity of car = 44km / hr.
Final Velocity of car = 0km / hr.
Acceleration = -5km/hr².

To Find :

Time taken to stop the car .

So , here use first equⁿ of motion which is ,

$\boxed{\red{\bf\dag v = u + at }}$

where ,

v is final Velocity.
u is Initial velocity.
a is acceleration.
t is time taken.

Now , substituting the respective values ,

$\tt:\implies v=u+at$

$\tt:\implies 0 = 44 + (-5)t$

$\tt:\implies -44 = -5t$

$\tt:\implies t=\dfrac{44}{5}$

$\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}$

$\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}$

6 0

3 years ago

Imagine you use Nitrogen as your gas. If you have the cold side as cold as you can without liquefying it (78 K), and run the hot

alina1380 [7]

Answer:

The efficiency of a Stirling engine is 74%

Explanation:

Given:

Temperature of gas when it is cold $T_{1} = 78$ K

Temperature of gas when it is hot $T_{2} = 300$ K

The efficiency of a stirling engine,

$\eta =1 - \frac{T_{1} }{T_{2} }$

$\eta = 1- \frac{78}{300}$

$\eta = 1-0.26$

$\eta = 0.74$

∴ $\eta = 74 \%$

Therefore, the efficiency of a Stirling engine is 74%

5 0

3 years ago

PLEASE HELP!!! Nico uses wire to connect a battery, a lightbulb, and a switch, but the bulb does not light up. Which might expla

Wewaii [24]

Its is C the answer is c lol

6 0

3 years ago

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