Answer:
A) Magnitude of flux; Φ_c = 77.97 μWb
B) Direction is inwards
Explanation:
A) The magnetic flux through a closed surface is zero. Thus, the summation of the flux through the two bases and the two bases and the curved surface equals zero and is written as:
Φ_s1 + Φ_s2 + Φ_c = 0
Where;
Φ_s1 is the flux through one end and it's given as; -36.4 μWb
(negative sign denotes the direction which is inwards)
Φ_s2 is the flux through the other end is given by a formula;
Φ_s2 = BA
Area is; A = πr²
Thus; Φ_s2 = Bπr²
We are given;
B = 2.33 mT = 2.33 x 10^(-3) T
r = 12.5 cm = 0.125 m
Thus,
Φ_s2 = 2.33 x 10^(-3) x π(0.125²)
Φ_s2 = 114.37 x 10^(-6) Wb
Thus;
Φ_s2 = 114.37 μWb
Since we know Φ_s1 and Φ_s2, let's plug them into the first equation to find the magnetic flux;Φ_c
Thus;
-36.4 μWb + 114.37 μWb + Φ_c = 0
Φ_c = -77.97 μWb
The magnitude is the absolute value which is;Φ_c = 77.97 μWb
B) Since the flux has a negative value, thus the direction is inwards
