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3 years ago

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A pair of electrically charged objects attract each other with a force of 4 N when they are a distance of 3 m apart. If their ch

arges stay the same, then what will be the attractive force between them when they are 6 m apart

1 answer:

Rainbow [258]3 years ago

7 0

Answer:

1 N

Explanation:

From coulomb's law,

The force of attraction between two charges is inversely proportional to the square of the distance between the charges.

From the question,

Assuming the charges are the same in both case,

F ∝ /r²....................... Equation 1

Fr² = k

F'r'² = Fr²........................... Equation 2

Where F' = First Force, r'² = First distance, F = second force, r² = second distance.

make F the subject of the equation,

F = F'r'²/r².................... Equation 3

Given: F' = 4 N, r' = 3 m, r = 6 m

Substitute into equation 3

F = 4(3²)/6²

F = 36/36

F = 1 N

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3 years ago

Imagine an alternative universe where the characteristic decay time of neutrons is 3 min instead of 15 min. All other properties

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