Can someone help me with this question? step by step pls

Mathematics

2 answers:

hammer [34]3 years ago

6 0

Answer:

Step-by-step explanation:

Sonja [21]3 years ago

5 0

In order to find the area of the web browser, recall that the equation to find the area is length*width. Since we know that the area is 24 square inches, we can create an equation:

x(x - 2) = 24
x^2 - 2x - 24 = 0

Factor:
(x - 6)(x + 4) = 0

{6, -4}

Since the length can't be a negative number, we can rule out -4 and affirm that x = 6.

Since we know the browser makes up 3/13 of the screen, we can make an equation with a variable where 'a' represents area of the computer:

(3/13) * a = 6
3a/13 = 6
3a = 78
a = 26

Now that we know the area, we can solve for the dimensions:

l*w = 26
(x + 7) * w = 26
(6 + 7) * w = 26
(13) * w = 26
w = 2

Input the width into the original equation:
l * (2) = 26
l = 13

The dimensions of the computer are 13 x 2.
The length of the browser is 6 inches.

Let me know if you need me to explain anything I did here.
-T.B.

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Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths. X2 y2 − 2x 2y −

Colt1911 [192]

Circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

<h3>What is the equation of circle?</h3>

The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of center point in the coordinate plane and measure of radius.

The standard form of the equation of the circle can be given as,

$(x-h)^2+(y-k)^2=r^2$

Here (h,k) is the center of the circle and (r) is the radius of the circle.

Lets arrange the first equation, in standard form of equation of circle as,

$x^2 +y^2 - 2x+ 2y -1 = 0 \\(x^2 - 2x) +(y^2+ 2y )= 1\\(x^2 - 2x+1) +(y^2+ 2y +1)= 1+1+1\\(x-1)^2+(y+1)^2=(\sqrt{3})^2$

The radius of this circle is √(3).

Lets arrange the second equation, in standard form of equation of circle as,

$x^2 +y^2 - 4x+ 4y - 10 = 0 \\(x^2 - 4x) +(y^2+ 4y )= 10\\(x^2 - 4x+4) +(y^2+ 4y +4)= 10+4+4\\(x-2)^2+(y+2)^2=(\sqrt{18})^2$

The radius of this circle is √(18).

Lets arrange the third equation, in standard form of equation of circle as,

$x^2 +y^2 - 8x - 6y - 20 = 0 \\(x^2 - 8x) +(y^2-6y )= 20\\(x^2 - 8x+16) +(y^2- 6y +9)= 10+16+9\\(x-4)^2+(y-3)^2=(\sqrt{45})^2$

The radius of this circle is √(45).

Similarly, radius of the forth, fifth, sixth and seventh circle is √(23), √(5), √(117) and √(46) units.

Hence, the circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

Learn more about the equation of circle here;

brainly.com/question/1506955

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2 years ago

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Find the difference -7/8 - 17/32= ? Please break it down

olasank [31]

Answer:-11/32

Step-by-step explanation:

-7/8 - (-17/32)

= -7/8 + 17/32

The highest common factor is 32