In order to find the area of the web browser, recall that the equation to find the area is length*width. Since we know that the area is 24 square inches, we can create an equation:
x(x - 2) = 24 x^2 - 2x - 24 = 0
Factor: (x - 6)(x + 4) = 0
{6, -4}
Since the length can't be a negative number, we can rule out -4 and affirm that x = 6.
Since we know the browser makes up 3/13 of the screen, we can make an equation with a variable where 'a' represents area of the computer:
(3/13) * a = 6 3a/13 = 6 3a = 78 a = 26
Now that we know the area, we can solve for the dimensions:
l*w = 26 (x + 7) * w = 26 (6 + 7) * w = 26 (13) * w = 26 w = 2
Input the width into the original equation: l * (2) = 26 l = 13
The dimensions of the computer are 13 x 2. The length of the browser is 6 inches.
Let me know if you need me to explain anything I did here. -T.B.
We know that applying the law of sines a/sin A=b/sin B---------> a*sin B=b*sin A <span>A = 80°, a = 24, b = 50 sin B=[b*sin A]/a-----> sin B=50*sin 80/24-----> sin B=2.0517
the sines value </span><span>can not be greater than 1 hence
