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Effectus [21]
3 years ago
6

Can someone help me with this question? step by step pls

Mathematics
2 answers:
hammer [34]3 years ago
6 0

Answer:

Step-by-step explanation:

Sonja [21]3 years ago
5 0
In order to find the area of the web browser, recall that the equation to find the area is length*width. Since we know that the area is 24 square inches, we can create an equation:

x(x - 2) = 24
x^2 - 2x - 24 = 0

Factor:
(x - 6)(x + 4) = 0

{6, -4}

Since the length can't be a negative number, we can rule out -4 and affirm that x = 6.

Since we know the browser makes up 3/13 of the screen, we can make an equation with a variable where 'a' represents area of the computer:

(3/13) * a = 6
3a/13 = 6
3a = 78
a = 26

Now that we know the area, we can solve for the dimensions:

l*w = 26
(x + 7) * w = 26
(6 + 7) * w = 26
(13) * w = 26
w = 2

Input the width into the original equation:
l * (2) = 26
l = 13

The dimensions of the computer are 13 x 2.
The length of the browser is 6 inches.

Let me know if you need me to explain anything I did here.
-T.B.
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Please solve the problem ​
jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.

Then you can eliminate <em>Y</em> by taking the sum

4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>

==>   <em>X</em> = (4<em>A</em> + <em>B</em>)/11

Similarly, you can eliminate <em>X</em> by using

-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>

==>   <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11

It follows that

X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}

Similarly, you would find

Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}

You can solve the second system in the same fashion. You would end up with

P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}

3 0
3 years ago
What is sixty-nine times sixty-nine?
Lunna [17]

Answer:

The answer is 4,761

8 0
3 years ago
A line intersects the points (14, -3) and (9, -11).
Lostsunrise [7]

Answer:

8/5 or 1 3/5

Step-by-step explanation:

5 0
4 years ago
It asks to "Solve the triangle then find the area of each triangle to the nearest tenth." I know how to find the sides and all b
Vladimir [108]

Answer:

Step-by-step explanation:

5 0
4 years ago
Solve using substitution.<br> Y = -x + 1<br> y = -2x + 8
sergey [27]
To find x- intercept the zero so substitute y=0
0=-x+1
X=1 thqt should be your answer
Hope this helped
Answer: x=1
3 0
3 years ago
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