Question

If f(x)=x^2 and g(x)=1÷2x+3 find g(f(-1))

Answer 1

ANSWER

$g(f( - 1)) = \frac{1}{5 }$

EXPLANATION

The given function is:

$f(x) = {x}^{2}$

and

$g(x) = \frac{1}{2x + 3}$

$g(f(x)) = g( {x}^{2} )$

$g(f(x)) = \frac{1}{2{x}^{2} + 3 }$

To find g(f(-1)), we substitute x=-1, to obtain;

$g(f( - 1)) = \frac{1}{2{( - 1)}^{2} + 3 }$

We simplify the square in the denominator to get,

$g(f( - 1)) = \frac{1}{2+ 3 }$

We now add the denominator to obtain;

$g(f( - 1)) = \frac{1}{5 }$