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Evgesh-ka [11]
3 years ago
8

The ratio of the number of boys to the number of girls at Liam's school is 4:5. There are 270 students at his school. Statement

1: The number of boys at school is 4/5 the number of girls.
Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0

Answer:

"statement 1: The number of boys at the school is \frac{4}5 of the number of girls." is true.

Step-by-step explanation:

Given:

Ratio of Number of boys to the number of girls = 4 : 5

Total number of students = 270

To find:

Number of boys in terms of number of girls = ?

Solution:

As per given statement,

Let, Number of boys = 4x

Let, Number of girls = 5x

Total number of students = Number of boys + Number of girls = 270

\Rightarrow 4x+5x =270\\\Rightarrow 9x=270\\\Rightarrow \bold{x  = 30}

Therefore, number of boys = 4 \times 30 = 120

And, number of girls = 5 \times 30 = 150

As per Statement 1:

Finding \frac{4}5 of the number of girls:

\dfrac{4}{5}\times 150 = 4 \times 30 = 120 = Number of boys.

Finding \frac{4}9 of the total number of students:

\frac{4}{9}\times 270= 4 \times 30 = 120 = Number of boys.

Number of boys is equal to \frac{4}9 of total number of students.

So, "statement 1: The number of boys at the school is \frac{4}5 of the number of girls." is true.

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One half of a number (use x) is equal to 8 less than the same number.
Rudiy27
Your answer is 16
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5 0
3 years ago
A sequence U1, U2,U3...... is defined by the relation Un +1 = 2Un +5. if U1 =2, find U1​
Harlamova29_29 [7]

Correct question:

a sequence U1, U2,U3...... is defined by the relation U_{n +1} = 2U_n +5. if U1 =2, find U2​ and U3

Answer:

U2 = 9

U3 = 23

Step-by-step explanation:

Given sequence;

U_{n +1} = 2U_n +5

U1 = 2

U2 = ?

U_{n +1} = 2U_n +5\\\\U_2 = 2(U_1) + 5\\\\U_2 = 2(2) + 5\\\\U_2 = 4 + 5\\\\U_2 = 9

Solving for U3;

U_3 = 2(U_2) + 5\\\\U_3 = 2(9) + 5\\\\U_3 = 18 + 5\\\\U_3 = 23

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3 years ago
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Hope these are the correct answers! :)
8 0
3 years ago
What is 56/108? they are even numbers so they can be simplified but I don't know how to do it right.
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That answer is simplified to 7/12
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Read 2 more answers
For the love of God help me !! I'm desperate for it tomorrow
Eduardwww [97]
Try to relax.  Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before.  But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.

Consider this:  (2)^a negative power = (1/2)^the same power but positive.

So: 
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.

What I just said in that paragraph was:  log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.

Now let's look at the problem:

log₂(x-1) + log(base 1/2) (x-2) = log₂(x)

Subtract  log₂(x)  from each side: 

log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0

Subtract  log(base 1/2) (x-2)  from each side:

log₂(x-1) - log₂(x)  =  - log(base 1/2) (x-2)  Notice the negative on the right.

The left side is the same as  log₂[ (x-1)/x  ]

==> The right side is the same as  +log₂(x-2)

Now you have:  log₂[ (x-1)/x  ]  =  +log₂(x-2)

And that ugly [ log to the base of 1/2 ] is gone.

Take the antilog of each side:

(x-1)/x = x-2

Multiply each side by 'x' :  x - 1 = x² - 2x

Subtract (x-1) from each side:

x² - 2x - (x-1) = 0

x² - 3x + 1 = 0

Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .

I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.


There,now.  Doesn't that feel better. 
 






4 0
2 years ago
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