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kati45 [8]
3 years ago
12

Probability that exactly one jack, one queen, and one king have been picked from the deck when the first ace turns up

Mathematics
1 answer:
mezya [45]3 years ago
6 0
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Question 5
Levart [38]

Answer:

7.8

Step-by-step explanation:

myjnhdgfb bgfb

4 0
3 years ago
-2x+2&gt;3x-8<br><br> 50 points
Blababa [14]

Given:

The inequality is

-2x+2>3x-8

To find:

The solution of the given inequality.

Solution:

We have,

-2x+2>3x-8

Isolate the variables terms on the left side.

-2x-3x>-2-8

-5x>-10

Divide both sides by -5 and change the inequality sign as we divide the equality by a negative value.

\dfrac{-5x}{-5}

x

Therefore, the correct option is D.

5 0
3 years ago
A university has 31,560 students. In a random sample of 180 students, 12 speak three or more languages. Predict the number of st
kodGreya [7K]
<h3>Hello there!</h3>

Here's the information given to us written out:

- 31560 total students

- 12/180 students speak 3 or more

To solve:

To solve this, use the probability from the survey of 180 students to make a reasonable estimate for the 31560 total students.

12/180 students were able to speak 3 or more languages. This proportion, of 12 students : 180 students can be adjusted.

Just like when simplifying fractions, both sides can have an operation (of multiplication or division) done to it and still be equivalent.

In this case, we want to set the side of total students to be equivalent to 31560 to get the estimated number of students that speak 3 or more languages.

To get the number to multiply both sides by:

31560 / 180 = 175 1/3 = 526/3

Now, carry out the operation - multiply both sides by that number.

12/180 = (12 * 526/3) / (180 * 526/3) = 2104 / 31560

So, out of 31560, using the same probability, around 2104 students would speak 3 or more languages.

Hope this helped!

3 0
4 years ago
Which is equivalent to vg*<br> Og<br> O 78%<br> 12784<br> 8 4x
Otrada [13]

Answer:

  (c)  (12th root of 8)^x

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c=a^{bc}\\\\\sqrt[n]{a}=a^{1 \! /n}

In this case, we have ...

  (\sqrt[3]{8})^{x/4}=8^{1/3\cdot x/4}=8^{x/12}=\boxed{\left(\!\sqrt[12]{8}\right)^x}

5 0
3 years ago
Is this equation have a solution or not<br> y = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D" id="TexFormula1" title=
Musya8 [376]

Answer:

No solution.

Step-by-step explanation:

y + 3x - 4y = 0 + 0.75x

- 3y + 3x = 0 + 0.75x

- 3y + 3x - 0.75x = 0 + 0.75x - 0.75x

- 3y + 2.25x = 0

7 0
3 years ago
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