Answer:
Side lengths = 1.68 ft and width = 3.36 ft.
Step-by-step explanation:
Let the side lengths of the window be L and the width = 2r ( r is also the radius of the semi-circle).
So we have
Perimeter = 2L + 2r + πr = 12
Area = 2rL + 0.5πr^2
From the first equation
2L = 12 - 2r - πr
Substitute for 2L in the equation for the area:
A = r(12 - 2r - πr) + 0.5πr^2
A = 12r - 2r^2 - πr^2 + 0.5πr^2
A = 12r - 2r^2 - 0.5πr^2
We need to find r for the maximum area:
Finding the derivative and equating to zero:
A' = 12 - 4r - πr = 0=
4r + πr = 12
r = 12 / ( 4 + π)
r = 1.68 ft.
So the width of the window = 2 * 1.68 = 3.36 ft.
Now 2L = 12 - 2r - πr
= 12 - 2*1.68 - 1.68π
= 3.36
L = 1.68.
C.60 its the same size and shape as the 60 above it
Supplementary angles add up to 180 degrees-
Let x = "the angle"
supplement angle = 2x + 12 // 12 more than twice the measurement of "the angle"
Supplement angle + "the angle" = 180 degrees
(2x + 12) + x = 180 degrees // 2x + 12 is the supplement angle
3x + 12 = 180 // Simplify
3x = 168 // Subtract 12 from both sides
x = 56 degrees // Divide both sides by 3
The measure of the angle is 56° and its supplement is 124°
Answer:
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