Answer:
c^6
Step-by-step explanation:
So, c is the same as c^ 1 ... therefore
c^5 x c
= c^5 x c^1
When we multiply two numbers with same base and different exponent, we add the exponents which in this case as 5 and 1
So c^5 x c^1
= c^(5+1)
= c^6
This is the simplest form
5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube
Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5x3+16 Group 2: -4x2-20x
Pull out from each group separately :
Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)
I hope it helps
Answer:
B. No
Step-by-step explanation:
In order for the relation to be a function, each X value must source exactly one arrow. The value -1 maps to two different values (2, -1), so the relation is NOT A FUNCTION.
<u>11 chairs at each table.</u> (157/14 = 11.214...)
<u>There will be 3 chairs left over.</u> (14x11 = 154 157-154 = 3)
