Split up each force into horizontal and vertical components.
• 300 N at N30°E :
(300 N) (cos(30°) i + sin(30°) j)
• 400 N at N60°E :
(400 N) (cos(60°) i + sin(60°) j)
• 500 N at N80°E :
(500 N) (cos(80°) i + sin(80°) j)
The resultant force is the sum of these forces,
∑ F = (300 cos(30°) + 400 cos(60°) + 500 cos(80°)) i
… … … + (300 sin(30°) + 400 sin(60°) + 500 sin(80°)) j N
∑ F ≈ (546.632 i + 988.814 j) N
so ∑ F has a magnitude of approximately 1129.85 N and points in the direction of approximately N61.0655°E.
<span>1.)the output is half of the input.
2.)the output is one more than twice the input.
3.)the output is the cube if the input.
4.)the output is six times the input.</span>
An arc of a circle has the same measure as the central angle that intercepts it.
Central angle 1 intercepts arc AB.
The measure of central angle 1 is the same as the measure of angle AB.
The measure of arc AB is 30 deg.
Answer:
B I think
Step-by-step explanation:
12% Of 79 Would be 9.48. Hope this helped :)
