Consecutive numbers would be like 2 and 3, or 7 and 8.
All we need to do is keep multiplying pairs of consecutive numbers until we get above 50.
1 × 2 = 2 (that's one.)
2 × 3 = 6 (two)
3 × 4 = 12 (three)
4 × 5 = 20 (four)
5 × 6 = 30 (five)
6 × 7 = 42 (six...)
<em>7 × 8 = 56 > 50</em>
We have a total of 6 numbers that equal the product of 2 consecutive intergers<em>
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Answer:
8.66214 x 10^11
Step-by-step explanation:
question may ask to round, so the answer may be simplified to 9 x 10^11
Answer:
27
Step-by-step explanation:
f(x) = 5x - 8
f(7) = 5(7) - 8 = 27
Area of a square is its side length squared...
A=s^2 solving for s...
s=√A
The perimeter of a square is 4 times its side length...
P=4s, and since s=√A
P=4√A, and we are told that A=100 in^2 so
P=4√100
P=4*10
P=40 in
Answer:
3
3•3•3= 27
Step-by-step explanation:
