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Ber [7]
3 years ago
7

g python Suppose the instructor of the course is convinced that the mean engagement of students who become knowledgeable in the

material (i.e., the eng1 population) is 0.75. Formulate null and alternative hypotheses for a statistical test that seeks to challenge this belief. What are the null and alternative hypotheses, and what type of test can be used
Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0

Answer:

Step-by-step explanation:

The null and alternative hypothesis that would seek to challenge this belief would be

Null hypothesis: u = 0.75

Alternative hypothesis: u =/ 0.75

The type of test to be used would be a one sample z test where one sample is drawn from the population and the mean engagement of students who become knowledgeable in the material is measured and tested in an experiment against the null hypothesis.

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A new plasma screen tv costs $2,970. A family makes a down payment of $720 and pays off the balance in 18 equal monthly payments
ratelena [41]
The monthly payment would be 125. 2,970-720=2,250 2,250/18=125 a month 
4 0
3 years ago
All 4 questions please
scZoUnD [109]

Answer:

  1. π = S/2πrh
  2. v = √2E/m
  3. b = (-7a+c)/2
  4. x =3y-1

Step-by-step explanation:

1.

S = 2\pi rh\\Divide\:both\sides\:of\:the\:equation\:by\:2rh\\\\\frac{S}{2rh} = \frac{2 \pi rh}{2 rh} \\\\\pi = \frac{S}{2rh}

2.

E = \frac{1}{2} mv^2\\\\E = \frac{mv^2}{2} \\\\Cross\:multiply\\\\2E =mv^2\\Divide\:both\:sides\:of\:the\:equation\:by\:m\\\frac{2E}{m} = \frac{mv^2}{m} \\\\\frac{2E}{m} =v^2\\Square\:root\:both\:sides\:of\:the\:equation\\\sqrt{\frac{2E}{m} } = \sqrt{v^2} \\\\\sqrt{\frac{2E}{m} } =v\\\\v =\sqrt{\frac{2E}{m} }

3.

7a+2b =c\\Isolate\:b\\\\2b =c-7a\\2b= -7a+c\\Divide\:both\:sides\:of\:the\:equation\:by \:2\\\frac{2b}{2} =\frac{-7a+c}{2} \\\\b = \frac{-7a+c}{2}

4.

y = \frac{1}{3} (x+1)\\\\y = \frac{x+1}{3}\\\\Cross\:multiply \\3y =x+1\\Isolate \:x\\3y -1=x\\\\x =3y-1

7 0
3 years ago
PLZ HELP!!!!!!!!!!!!!
rewona [7]
4th from the top:  1/2base x height
5 0
3 years ago
Read 2 more answers
(10-3)*2+(5-14/2 help
Dafna11 [192]
2(10-3) distribute = 2*10 is 20 and 2*3 is 6
20-6+(5-14/2)
now 20-6 is 14
14+(5-14/2)
now 14/2 is 7
14+(5-7)
now 5-7 is -2
14+-2
is 12 
the answer is 12
but if you want to you can do 12/3 to get the greatest common factor 
which is 4
hope i help you :P 
6 0
3 years ago
Read 2 more answers
Let f(t) give the number of liters of fuel oil burned in t days, and w(r) the liters burned in r weeks. Find a formula for w by
viktelen [127]

Answer:

7 f(t)

Step-by-step explanation:

So, our f(t) is the number of liters burned in t days. If t is 1, f(t)=f(1) and so on for every t.

w(r) id the number of liters in r weeks. This is, in one week there are w(1) liters burned.

As in one week there are 7 days, we can replace the r, that is a week, by something that represents 7 days. As 1 day is represented by t, one week can be 7t (in other words r = 7t). So, we have that the liters burned in one week are:

w(r) = w[7f(t)]

So, we represented the liters in one week by it measure of days.

So, we can post that the number of liters burned in 7 days is the same as the number of liters burned 1 day multiplied by 7 times. So:

w (r) = w[7 f(t)] = 7 f(t)

Here we hace the w function represented in terms of t instead of r.

3 0
3 years ago
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