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Ber [7]
3 years ago
7

g python Suppose the instructor of the course is convinced that the mean engagement of students who become knowledgeable in the

material (i.e., the eng1 population) is 0.75. Formulate null and alternative hypotheses for a statistical test that seeks to challenge this belief. What are the null and alternative hypotheses, and what type of test can be used
Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0

Answer:

Step-by-step explanation:

The null and alternative hypothesis that would seek to challenge this belief would be

Null hypothesis: u = 0.75

Alternative hypothesis: u =/ 0.75

The type of test to be used would be a one sample z test where one sample is drawn from the population and the mean engagement of students who become knowledgeable in the material is measured and tested in an experiment against the null hypothesis.

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A square and a rectangle have the same perimeter. The rectangle is 13 cm long and 7 cm wide.
lorasvet [3.4K]

<u>Solving</u>

Knowing that we have the information needed we will first find the perimeter of the rectangle.

Rectangle:
Length: 13cm

Width: 7cm  

Formula: L+L+W+W

13+13+7+7 = 40cm

Meaning the perimeter is 40cm and we can use this to find the length of a square. From general knowledge we know that all sides of a square is equal.

So if we divide the 4 sides by 40 we will get our answer.

40 ÷ 4 = 10

So B would be our answer...

<u>Statement</u>

<u />

Therefore the length of a side of the square is 10cm, meaning answer B is correct.

5 0
2 years ago
5.The ratio of the age of a mother and her son is 5:2. If the
Andreyy89

Answer:

The age of mother is:

40 years

Step-by-step explanation:

2a = 5b

b = 16

a = age of a mother

b = age of her son

2a = 5*16

2a = 80

a = 80/2

a = 40

probe:

2*40 = 5*16 = 80

5 0
3 years ago
(It’s a 6 not a 5)<br> A-dot 1<br> B-dot 2<br> C-dot 3<br> D-dot 4
Taya2010 [7]
A- dot 1 . that’s the answer but it’s making me type 20 words.
8 0
2 years ago
The change in water vapor in a cloud is modeled by a polynomial function, C(x). C(x) = x^3+ 5x^2+3x+30 Describe how to find the
kari74 [83]

Answer:

Suppose the equation that describes the change in water vapor in a cloud (y) with respect to temperature (x): C(x) = x³ - 4x² - 7x + 10

You find the x-intercepts of the cubic equation by finding the roots. Let y be zero:

x³ - 4x² - 7x + 10 = 0

Now, find possible factors of the constant term in the equation: 10. These could be 1, 2, 5, and 10. Suppose we choose 1. We substitute x=1. If the answer is zero, then x=1 is one of the roots.

(1)³ - 4(1)² - 7(1) + 10 = 0

Hence, x=1 or x-1 = 0 is one of the roots. We use this to manipulate the rest of the terms in the original equation, such that you can factor out (x-1). Substitute -x² - 3x² to -4x³ because they are just equal. Same is true for +3x - 10x for -7x:

x³ -x² - 3x²+3x - 10x + 10 = 0

Factor out like terms such that they have a common factor of (x-1) as much as possible.

x³ -x² = x²(x-1)

- 3x²+3x = -3x(x-1)

- 10x + 10 = -10(x-1)

The factored equation is:

x²(x-1)-3x(x-1)-10(x-1) = 0

Factor out (x-1):

(x-1)(x²-3x-10) = 0

Now, we have the quadratic equation left to be solved:x²-3x-10

Use the quadratic formula to find the roots:

x = [-b +/- √(b²-4ac)]/2a,

The a, b and c coefficients are based on the general form of the quadratic equation: ax² + bx + c. Hence, a=1, b=-3 and c=-10. Substituting the values:

x = [-(-3) +/- √((-3)²-4(1)(-10))]/2(1)

x = 5, -2

Therefore, the roots of the cubic equations are x = 1, x = 5 and x =- 2. These are the x-intercepts of the equation. At temperatures °C, 5°C and -2°C, there is no change in water vapor in a cloud. The graph is shown in the attached picture

Step-by-step explanation:

7 0
2 years ago
The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice
777dan777 [17]
If period of f(\theta) is one-half the period of g(\theta) and
<span>g(\theta)  has a period of 2π, then T_{g} =2T_{f}=2 \pi and T_{f}= \pi.
</span>
To find the period of sine function f(\theta)=asin(b\theta+c) we use the rule T_{f}= \frac{2\pi}{b}.
<span /><span />
f is sine function where f (0)=0, then c=0; with period \pi, then f(\theta)=asin 2\theta, because T_{f}= \frac{2 \pi }{2} = \pi. 

To find a we consider the condition f( \frac{ \pi }{4} )=4, from where asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4.

If the amplitude of f(\theta) is twice the amplitude of g(\theta) , then g(\theta) has a product factor twice smaller than f(\theta) and while period of g(\theta)<span> </span> is 2π and g(0)=0, we can write g(\theta)=2sin\theta.






8 0
2 years ago
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