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vova2212 [387]
3 years ago
7

How can this be solved? (With explanation please.) Sorry about the writing and marks.

Mathematics
1 answer:
GalinKa [24]3 years ago
4 0
He answer is -24. Hope his helps

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To describe a specific arithmetic sequence, Elijah wrote the recursive formula:
11111nata11111 [884]

Answer:

t_{n}  = 30 + 7n, where, n = 0, 1, 2, 3, 4, .........

Step-by-step explanation:

Given the arithmetic sequence in recursive formula.

f(0) = 30 and f(n + 1) = f(n) + 7 ......... (1)

Therefore, putting n = 0 in equation (1) we get f(1) = f(0) + 7 = 30 + 7 = 37 {Since, f(0) is given to be 30}

Again, putting n = 1 in equation (1) we get f(2) = f(1) + 7 = 37 + 7 = 44

And, putting n = 2 in equation (1) we get f(3) = f(2) + 7 = 44 + 7 = 51

and so on.

Therefore, the arithmetic sequence is 30, 37, 44, 51, .......

Therefore, the linear equation of this sequence is given by t_{n}  = 30 + 7n, where, n = 0, 1, 2, 3, 4, .........

(Answer)

3 0
3 years ago
What is the midpoint of the segment shown below? (-2, 3) (10, 3)
sergeinik [125]

Answer:

That point P(x,y)

x = (-2+10)/2 = 4

y = (3+3)/2 = 3

=> P (4,3)

5 0
3 years ago
An angle bisector always creates two acute angles. find a counterexample to show that the conjecture is false.
sweet-ann [11.9K]
An acute angle is an angle that is less than 90°. An angle bisector is a ray drawn along an angle that bisects it into two equal and adjacent parts. Now, if the total angle is, say 270°, which is more than a half circle, it would result to two 135-degree angles. In this case, the angle is no longer acute, but obtuse.
5 0
3 years ago
“I think of a number, multiply it by 2, subtract 3 and multiply the result by 4."
Scorpion4ik [409]

Answer:

33x2=66

66-3=62

62x4=248

Is this a question for a test cause if it is i'm gonna feel embarrassed

5 0
3 years ago
The population of a town is 6500 and is increasing at a rate of 4% each year. Create a function for this scenario. At this rate,
Stella [2.4K]

Answer:

P_4 = 7604.08

Step-by-step explanation:

If the population increases at a rate of 4% per annum, then:

In year 1:

P_1 = P_0 + 0.04P_0

Where P_0 is the initial population and P_n is the population in year n

In year 2

P_2 = P_1 + 0.04P_1

It can also be written as:

P_2 = P_0 + 0.04P_0 + 0.04 (P_0 + 0.04P_0)

Taking out common factor P_0

P_2 = (1 + 0.04) (P_0) + 0.04P_0 (1 + 0.04)

Taking out common factor (1 + 0.04)

P_2 = (1 + 0.04) (P_0 + 0.04P_0)

Taking out again common factor P_0

P_2 = (1 + 0.04) (1 + 0.04) P_0

Simplifying

P_2 = P_0 (1 + 0.04) ^ 2


So

P_n = P_0 (1 + 0.04) ^ n

This is the equation that represents the population for year n

Then, in 4 years, the population will be:

P_4 = P_0 (1 + 0.04) ^ 4\\P_4 = 6500(1 + 0.04) ^ 4\\P_4 = 7604.08

3 0
3 years ago
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