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Viktor [21]
4 years ago
8

Someone please help me with this question !!

Mathematics
1 answer:
yarga [219]4 years ago
6 0
The answer is 12^8/9
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3. Landon has 3 black shirts, 2 white shirts, and 2 blue shirts. He also has 2
IRINA_888 [86]

Answer:

3/5 probability. hope this helps

Step-by-step explanation:

6 0
3 years ago
Their sum is − 1/3 and their difference is 18
Rina8888 [55]

Answer:x=53/6 and y=-55/6

Step-by-step explanation:

Let the first number x

Second number b y

Sum of the numbers x+y=-1/3

x-y=18

Solve simultaneously

Using elimination method

We get

2y=-55/3

y=-55/6

Substitute for y in equation 1

x+55/6=18

x=18-55/6

x=53/6

6 0
3 years ago
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
Answer both parts please, file included
sergeinik [125]
2w+4=35 
w=15.5
I hoped i helped 

3 0
4 years ago
Determine the sample size needed to construct a 99​% confidence interval to estimate the average GPA for the student population
Volgvan

Answer: n = 14

Step-by-step explanation: margin of error = critical value × σ/√n

Where σ = population standard deviation = 1

n = sample size = ?

We are to construct a 99% confidence interval, hence the level of significance is 1%.

The critical value for 2 tailed test at 1% level of significance is gotten from a standard normal distribution table which is 2.58

Margin of error = 0.7

0.7 = 2.58×1/√n

0.7 = 2.58/√n

By cross multipying

0.7×√n = 2.58

By squaring both sides

0.7^2 × n = 2.58^2

0.49 × n = 6.6564

n = 6.6564/0.49

n = 14

3 0
4 years ago
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