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ser-zykov [4K]
3 years ago
15

You’re probably familiar with the sour taste of acidic lemon juice and the slippery feel of alkaline (basic) soap. In fact, thes

e characteristics were used to identify acids from bases long ago. Today, we understand much more about acidity and alkalinity, far beyond taste and feel. Acids are most simply defined as proton donors. They have a ph of below 7. They are substances that react with water to produce H3O+ (hydronium) ions (after all, H2O + one proton → H3O+ ). When you add an acid to water the water acts as a base, accepting protons from the acid. Bases are most simply defined as proton acceptors. They have a ph of above 7. They react with water to produce OH- (hydroxide) ions (H2O - one proton → OH-). When you add a base to water the water acts as an acid, donating protons to the base.1. Citric acid H3C6H5O7 is the substance that gives lemon juice and other citrus fruit juices a sour taste. How many grams of citric acid are present in 125mL of a 0.400M citric acid solution?
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
5 0

Answer:

9.606 grams of citric acid are present in 125 mL of a 0.400 M citric acid solution.

Explanation:

Molarity : It is defined as the number of moles of solute present in one liter of solution.  Mathematically written as:

Molarity=\frac{\text{Moles of solute}}{\text{volume of solution in L}}

Moles of citric acid  = n

Volume of the citric acid  solution = 125 mL  =125 × 0.001 L= 0.125 L

(1 mL = 0.001L)

Molarity of the citric acid  solution = 0.400 M

0.400 M=\frac{n}{0.12 5L}

n  = 0.400 M × 0.125 L = 0.05 moles

Mass of 0.05 moles of citric acid :

0.05 mol\times 192.12 g/mol=9.606 g

9.606 grams of citric acid are present in 125 mL of a 0.400 M citric acid solution.

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Which of the newman structures below represents this conformation of 2-methyl-3-pentanol, as viewed along the c2-c3 bond?
castortr0y [4]

Answer:

(4) option is correct

Explanation:

Given that,

The conformation of 2-methyl-3-pentanol, as viewed along the C₂-C₃ bond.

We need to find the Newman structures

Using given structures

The structure of 2- methyl-3- pentanol is shown in figure.

Through C₂-C₃ carbon shown the structure of Newman projection in figure.

Here, carbon 2 is in front side and carbon 3 is in back side in the figure.

Hence, (4) option is correct.

5 0
3 years ago
Which of the following represents a chemical change?
Snezhnost [94]
The answer is B.) Freezing of water
3 0
3 years ago
What is the lowest temperature that a substance can reach?
kobusy [5.1K]
Absolute zero that means cooling - 0 degree
3 0
3 years ago
How many calories are absorbed in a process that absorbs 0.128 joules?
earnstyle [38]

Answer:

There are 0.0305 calories in 0.128 joules

Explanation:

Given that,

Heat absorbed, Q = 0.128 J

We need to find the heat energy absorbed in calories.

We know that the relation between joules and calories is as follows :

1 calorie = 4.184 J

1 J = (1/4.184) J

So,

0.128\ J=\dfrac{0.128 }{4.184}\\\\=0.0305\ cal

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7 0
3 years ago
(3) A 10.00-mL sample of 0.1000 M KH2PO4 was titrated with 0.1000 M HCl Ka for phosphoric acid (H3PO4): Ka1= 7.50x10-3; Ka2=6.20
shtirl [24]

Answer:

The pH of this solution is 1,350

Explanation:

The phosphoric acid (H₃PO₄) has three acid dissociation constants:

HPO₄²⁻ ⇄ PO4³⁻ + H⁺        Kₐ₃ = 4,20x10⁻¹⁰  (1)

H₂PO₄⁻ ⇄ HPO4²⁻ + H⁺    Kₐ₂ = 6,20x10⁻⁸   (2)

H₃PO₄ ⇄ H₂PO4⁻ + H⁺       Kₐ₁ = 7,50x10⁻³   (3)

The problem says that you have 10,00 mL of KH₂PO₄ (It means H₂PO₄⁻) 0,1000 M and you add 10,00 mL of HCl (Source of H⁺) 0,1000 M. So you can see that we have the reactives of the equation (3).

We need to know what is the concentration of H⁺ for calculate the pH.

The moles of H₂PO₄⁻ are:

10,00 mL × ( 1x10⁻⁴ mol / mL) = 1x10⁻³ mol

The moles of H⁺ are, in the same way:

10,00 mL × ( 1x10⁻⁴ mol / mL) = 1x10⁻³ mol

So:

H₃PO₄   ⇄      H₂PO4⁻         +        H⁺           Kₐ₁ = 7,50x10⁻³   (3)

X mol     ⇄  (1x10⁻³-X) mol  + (1x10⁻³-X) mol                            (4)

The chemical equilibrium equation is:

Kₐ₁ = ([H₂PO4⁻] × [H⁺] / [H₃PO₄]

So:

7,50x10⁻³ = (1x10⁻³-X)² / X

Solving the equation you will obtain:

X² - 9,5x10⁻³ X + 1x10⁻⁶ = 0

Solving the quadratic formula you obtain two roots:

X = 9,393x10⁻³ ⇒ This one has no chemical logic because solving (4) you will obtain negative H₂PO4⁻ and H⁺ moles

X = 1,065x10⁻⁴

So the moles of H⁺ are : 1x10⁻³- 1,065x10⁻⁴ : 8,935x10⁻⁴ mol

The reaction volume are 20,00 mL (10,00 from both KH₂PO₄ and HCL)

Thus, the molarity of H⁺ ([H⁺]) is: 8,935x10⁻⁴ mol / 0,02000 L = 4,468x10⁻² M

pH is -log [H⁺]. So the obtained pH is 1,350

I hope it helps!

5 0
3 years ago
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