Question

In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. how many lone pairs of electrons are present in the lewis structure of calcium sulfide?

Answer 1

Below are the choices that can be found elsewhre:

A. one 
B. two 
C. three 
D. four 
E. none

The answer is D which is four  Ca has given up 2 electrons to sulfur with six which makes 8 e-, or 4 pairs.

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Answer 2

Answer:

2

Explanation:

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or $1s^22s^22p^63s^23p^64s^2$

There are 2 valence electrons of Calcium.

Sulfur is the element of sixteenth group and third period. The electronic configuration of sulfur is - 2, 8, 6 or $1s^22s^22p^63s^23p^4$

There are 6 valence electrons of sulfur.

The Lewis structure is drawn in such a way that the octet of each atom is complete.  

Thus, calcium loses two electrons to sulfur and sulfur accepts these electrons to form ionic bond.

Calcium sulfide, $CaS$ is formed when 2 valence electrons of calcium are loosed and they are gained by sulfur atom.

Thus, the valence electrons are shown by dots in Lewis structure. The structure is shown in image below.

From the structure, the lone pairs on the structure are: -2