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GarryVolchara [31]
3 years ago
10

Give two reason (evidence) Why we think the Earth's outer core is liquid

Chemistry
1 answer:
mihalych1998 [28]3 years ago
5 0
The outer-core temperature has exceeded the melting point of iron/nickel, which is a function of pressure casing it to be liquid

that's the only reason I got. sorry!
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Which of the following gases in Earth's atmosphere would you expect to find as molecules and which as individual atoms? Explain
azamat

Answer: argon

Explanation:

7 0
3 years ago
2Al + 6HCl → 2AlCl3 + 3H2<br> If 85.0 grams of HCl react, how many moles of H2 are produced?
Murrr4er [49]

Answer:

1.17 mol

Explanation:

Step 1: Write the balanced equation

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

Step 2: Calculate the moles corresponding to 85.0 g of HCl

The molar mass of HCl is 36.46 g/mol.

85.0 g × 1 mol/36.46 g = 2.33 mol

Step 3: Calculate the number of moles of H₂ produced from 2.33 moles of HCl

The molar ratio of HCl to H₂ is 6:3.

2.33 mol HCl × 3 mol H₂/6 mol H₂ = 1.17 mol H₂

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2 years ago
How many moles of h2o will be produced from 42.0 grams of h2o2
lisabon 2012 [21]

The answer is 44.6 mol


5 0
3 years ago
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What two pieces of information does the ATOMIC NUMBER give you?*
DiKsa [7]

Answer: Identifies the number of protons a single atom of the element contains.

Explanation: The atomic number helps people identify elements according to the number of protons one atom of the element has. It essentially defines the element. While having a neutral charge, it also provides the number of electrons the element has (in one atom).

8 0
2 years ago
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How much energy (in Joules) would it take to warm 3.11 grams of gold by 7.7 oC
Reptile [31]

Answer:

It would take 3.11 J to warm 3.11 grams of gold

Explanation:

Step 1: Data given

Mass of gold = 3.11 grams

Temperature rise = 7.7 °C

Specific heat capacity of gold = 0.130 J/g°C

Step 2: Calculate the amount of energy

Q = m*c*ΔT

⇒ Q = the energy required (in Joules) = TO BE DETERMINED

⇒ m = the mass of gold = 3.11 grams

⇒ c = the specific heat of gold = 0.130 J/g°C

⇒ ΔT = The temperature rise = 7.7 °C

Q = 3.11 g * 0.130 J/g°C * 7.7 °C

Q = 3.11 J

It would take 3.11 J to warm 3.11 grams of gold

4 0
3 years ago
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