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3 years ago

The approximate value of 5.1 million x 2.2 thousand is? use scientific notation

Mathematics

2 answers:

Sliva [168]3 years ago

7 0

11,220,000,000 is the answer for this question.

Nezavi [6.7K]3 years ago

7 0

The answer is 1.122*10^10

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What is the not number in this sequence?

Oksanka [162]

The answer is: "123454321"
Hope this helps!

8 0

3 years ago

Which definite integral approximation formula is this: the integral from a to b of f(x)dx ≈ (b-a)/n * [<img src="https://tex.z-d

Stella [2.4K]

The answer is most likely A.

The integration interval [a, b] is split up into n subintervals of equal length (so each subinterval has width (b - a)/n, same as the coefficient of the sum of y terms) and approximated by the area of n rectangles with base (b - a)/n and height y.

n subintervals require n + 1 points, with

x₀ = a

x₁ = a + (b - a)/n

x₂ = a + 2(b - a)/n

and so on up to the last point x = b. The right endpoints are x₁, x₂, … etc. and the height of each rectangle are the corresponding y 's at these endpoints. Then you get the formula as given in the photo.

• "Average rate of change" isn't really relevant here. The AROC of a function G(x) continuous* over an interval [a, b] is equal to the slope of the secant line through x = a and x = b, i.e. the value of the difference quotient

(G(b) - G(a) ) / (b - a)

If G(x) happens to be the antiderivative of a function g(x), then this is the same as the average value of g(x) on the same interval,

$g_{\rm ave}=\dfrac{G(b)-G(a)}{b-a}=\dfrac1{b-a}\displaystyle\int_a^b g(x)\,\mathrm dx$

(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

• "Trapezoidal rule" doesn't apply here. Split up [a, b] into n subintervals of equal width (b - a)/n. Over the first subinterval, the area of a trapezoid with "bases" y₀ and y₁ and "height" (b - a)/n is

(y₀ + y₁) (b - a)/n

but y₀ is clearly missing in the sum, and also the next term in the sum would be

(y₁ + y₂) (b - a)/n

the sum of these two areas would reduce to

(b - a)/n = (y₀ + 2 y₁ + y₂)

which would mean all the terms in-between would need to be doubled as well to get

$\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)$

7 0

3 years ago

Please help and explain question 12

il63 [147K]

The sunflower is 2.387 meters tall.

The question is asking: which rounding will result in the greatest value?

To see, we need to round 2.387 to meter, tenth meter, and hundredth meter.

Meter - 2 meters

Tenth meter - 2.4 meters

Hundredth meter - 2.39 meters

As you see, rounding to the tenth meter gives the greatest value of 2.4. Therefore, Bahir should use a decimal rounded to the tenth meter.

3 0

3 years ago

If y varies inversely as x, and y=6 when x=3. Then find the value of y when x=32

s2008m [1.1K]

Answer: y = 18/32

Step-by-step explanation: Okay the equation is xy = k

You plug in x and y.

(3)(6) = k

18 = k

To get the value of y when x = 32 you plug in 32.

Use this equation now y = k/x

Now it is y = 18/32

And that is your answer!

7 0

3 years ago

The temperature on Wednesday evening was -°5 Fahrenheit. The temperature decreased another 8° throughout the night. Wjat was the

____ [38]

The temperature on Thursday morning would be -13°F.

Since the temperature decreased throughout the night, this is a subtraction problem.

-5 - 8 = - 13

4 0

3 years ago