Ask question

Ask question

All categories

3 years ago

14

The approximate value of 5.1 million x 2.2 thousand is? use scientific notation

2 answers:

Sliva [168]3 years ago

7 0

11,220,000,000 is the answer for this question.

Nezavi [6.7K]3 years ago

7 0

The answer is 1.122*10^10

You might be interested in

Please help me with this

LuckyWell [14K]

Answer:

draw a box put 8 sides color 5 then you get it

Step-by-step explanation:

i am only here for the points XD

5 0

3 years ago

Read 2 more answers

A pet store has 12 puppies, including 3 poodles, 5 terriers, and 4 retrievers. if rebecka and aaron, in that order, each se

GuDViN [60]

Total number of puppies = 12
Where;
Poodles = 3
Terriers = 5
Retrievers = 4

After Rebecca selects a poodle, total number of puppies remaining = 12 -1 =11
Then,
Probability of Aaron selecting a retriever:

P(R) = Number of retrievers/New total = 4/11

7 0

3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer

AfilCa [17]

Answer:

$\theta = \cos^{-1} (\pm \frac{1}{2} )$

Step-by-step explanation:

The function is $g(\theta) = 8\cdot \theta - 2\cdot \tan \theta$ , whose first derivative is:

$g'(\theta) = 8 - 2\cdot \sec^{2}\theta$

Let equalize the derivative to zero:

$8 - 2\cdot \sec^{2}\theta=0$

$\sec^{2}\theta = 4$

$1 = 4\cdot \cos^{2}\theta$

$\cos \theta = \pm\sqrt {\frac{1}{4} }$

$\cos \theta = \pm \frac{1}{2}$

The solutions are given by the following inverse trigonometric function:

$\theta = \cos^{-1} (\pm \frac{1}{2} )$

6 0

3 years ago

When a new machine is not functioning properly, 15% of the items produced are defective. Assume that we will randomly select 5 p

cestrela7 [59]

Answer:

P(X<=2) = 0.9736

Step-by-step explanation: Please find the attached file for the solution

7 0

3 years ago

Which equations represent exponential growth? Which equations represent exponential decay? Drag the choices into the boxes to co

Norma-Jean [14]

Answer:

Exponential growth functions are:

$A=20000(1.08)^{t}$

$A=40(3)^{t}$

$A=1700(1.07)^{t}$

Exponential decay functions are:

$A=80(\frac{1}{2})^{t}=80(0.5)^{t}$

$A=1600(0.8)^{t}$

$A=1700(0.93)^{t}$

Step-by-step explanation:

Given:

An exponential function is of the form $y=ab^{x}$ , where, $a\ne 0$ .

Now, if a > 0 and b > 1, then the exponential function represent exponential growth.

If a > 0 and 0 < b < 1, then the exponential function represent exponential decay.

Let us check each function now.

Option 1: $A=20000(1.08)^{t}$

Here, $a = 20000, b = 1.08$

As 1.08 > 1, the function is exponential growth.

Option 2: $A=80(\frac{1}{2})^{t}=80(0.5)^{t}$

Here, $a = 80, b = 0.50$

As 0.5 < 1, the function is exponential decay.

Option 3: $A=1600(0.8)^{t}$

Here, $a = 1600, b = 0.8$

As 0.8 < 1, the function is exponential decay.

Option 4: $A=40(3)^{t}$

Here, $a = 40, b = 3$

As 3 > 1, the function is exponential growth.

Option 5: $A=1700(1.07)^{t}$

Here, $a = 1700, b = 1.07$

As 1.07 > 1, the function is exponential growth.

Option 6: $A=1700(0.93)^{t}$

Here, $a = 1700, b = 0.93$

As 0.93 < 1, the function is exponential decay.

5 0

3 years ago