Andrew solves 6x2=12x by using the quadratic formula. What values does he use for a, b, and c? a = (Put the number only in the b
lank - not the "a =") b = (Put the number only in the blank - not the "b =") c = (Put the number only in the blank - not the "c =")
1 answer:
Answer:
a=6, b=-12, and c=0
Step-by-step explanation:
The standard format for the quadratic formula is ax^2+bx+c (=0).
If we rearrange the numbers given to look like this formula, we will find the values of a, b, and c.
6x^2=12x We can move over the 12x to the other side.
6x^2-12x=0 There is no visible value of c, but since there is no term without a variable, c=0
6x^2-12x+0=0
So a=6, b=-12, and c=0
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