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lys-0071 [83]
3 years ago
9

Andrew solves 6x2=12x by using the quadratic formula. What values does he use for a, b, and c? a = (Put the number only in the b

lank - not the "a =") b = (Put the number only in the blank - not the "b =") c = (Put the number only in the blank - not the "c =")
Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Answer:

a=6, b=-12, and c=0

Step-by-step explanation:

The standard format for the quadratic formula is ax^2+bx+c (=0).

If we rearrange the numbers given to look like this formula, we will find the values of a, b, and c.

6x^2=12x    We can move over the 12x to the other side.

6x^2-12x=0   There is no visible value of c, but since there is no term without a variable, c=0

6x^2-12x+0=0

So a=6, b=-12, and c=0

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x = 3y + 11
x = 3(16) + 11
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