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lys-0071 [83]
3 years ago
9

Andrew solves 6x2=12x by using the quadratic formula. What values does he use for a, b, and c? a = (Put the number only in the b

lank - not the "a =") b = (Put the number only in the blank - not the "b =") c = (Put the number only in the blank - not the "c =")
Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Answer:

a=6, b=-12, and c=0

Step-by-step explanation:

The standard format for the quadratic formula is ax^2+bx+c (=0).

If we rearrange the numbers given to look like this formula, we will find the values of a, b, and c.

6x^2=12x    We can move over the 12x to the other side.

6x^2-12x=0   There is no visible value of c, but since there is no term without a variable, c=0

6x^2-12x+0=0

So a=6, b=-12, and c=0

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3 years ago
It said i need to simplify. how do i
horrorfan [7]

Answer:

The equation relating the volume of water, y to the volume of flour, x is therefore;

y = 1/3×x

The quantity of water per liter of flour = 1/3 liters

The quantity of flour per liter of water = 3 liters

Step-by-step explanation:

The given information from the graph are;

At 0 liters of water, the volume of flour = 0 liters of flour

At 1 liter of water, the volume of flour = 3 liters of flour

The relationship between the volume of water and flour is linear given s follows;

The equation for a linear relationship is y = m·x + c

m = The gradient or slope of the line, c = the y-intercept

In the graph the y-intercept = 0 therefore, c = 0

The slope, m is (change in y-coordinate)/(Change in x-coordinate)

∴ m = (1 - 0)/(3 - 0) = 1/3

The equation relating the volume of water, y to the volume of flour, x is therefore;

y = 1/3×x

Such that when the question asks, how many liter of water is used per liter of flour, we get;

y = 1/3× 1 = 1/3 liters

Similarly when the question asks, how many liter of flour is used per liter of water, we get;

1 = 1/3×x

x = 3 × 1 = 3 liters.

4 0
3 years ago
Solve the system of equations.<br> <img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7By%3D220x-160%7D%20%5Catop%20%7By%3
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\begin{cases} y=220x-160\\ y=20x^2-400 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{\stackrel{\textit{\Large y}}{220x-160}~~ = ~~20x^2-400} \\\\\\ -160=20x^2-220x-400\implies 0=20x^2-220x-240 \\\\\\ 0=20(x^2-11x-12)\implies 0=x^2-11x-12 \\\\\\ 0=(x-12)(x+1)\implies x= \begin{cases} 12\\ -1 \end{cases}

\dotfill\\\\ x=12\qquad \qquad \stackrel{\textit{substituting on the 1st equation}}{y=220(12)-160}\implies y=2480 \\\\\\ x=-1\qquad \qquad \stackrel{\textit{substituting on the 1st equation}}{y=220(-1)-160}\implies y=-380 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (12~~,~~2480)\qquad (-1~~,~~-380)~\hfill

4 0
2 years ago
Goran is riding his bicycle. He rides for 22.5 kilometers at a speed of 9 kilometers per hour. For how many hours does he ride?
astra-53 [7]

Answer: He rides for 2.5 hours or 2 and a half hours.

Step-by-step explanation:

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He rides 9 kilometers per hour.

Divide the total by the amount of kilometers that he rides.

\frac{22.5}{9}=2.5h

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