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nasty-shy [4]
4 years ago
11

How much agarose powder would you need to use (include units!) if you only needed 40 ml of agarose gel and the package recipe st

ates ‘use 6 grams of agarose powder dissolved in 500 ml of water’?
Chemistry
1 answer:
motikmotik4 years ago
7 0

The rule of three is a way to solve problems of proportionality between three known values and one unknown.  <u>This is an operation of finding the fourth term of a proportion knowing the other three</u>.

We can use the rule of three to solve this problem in this way,

500 mL →  6 grams

40 mL  →     x

This is the same as saying: if in 500 mL there should be 6 grams of agarose powder then in 40 mL how many grams should there be?

So,

x = 40 mL x \frac{6 g}{500 mL} → x = 0.48 g = 480 mg

Then, you need to dissolved 480 mg of agarose powder in 40 mL of water to meet the recipe.

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Please help me thank you :)
LenaWriter [7]

Answer:

D. 3220

Explanation:

1 km equals 1000 m, so 3.22 km is

3220 m

5 0
4 years ago
Read 2 more answers
6.<br> What is the acceleration of a 24 kg mass pushed by a 6 N force?<br> I jus need number 6
Setler79 [48]

The acceleration : 0.25 m/s²

<h3>Further explanation</h3>

Given

mass = m = 24 kg

Force = F = 6 N

Required

The acceleration

Solution

Newtons' second law :

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

ΣF =  m x a

\large {\boxed {\bold {a = \frac {\sum F} {m}}}

Input the value :

6 N = 24 kg x a

a = 6 : 24

a = 0.25 m/s²

3 0
3 years ago
Read 2 more answers
A sample of hydrogen peroxide (H202) has 2.0 grams of hydrogen (H) and 32 grams of oxygen (O). What is the percent composition o
Leto [7]

Answer:

O = 94.117%

H = 5.882%

Explanation:

Hydrogen peroxide (H202) Molar Mass = 34g

OH 1-  17g/mol

H 1+ = 1g/mol

O = 16g/mol

2 Grams H

32 grams O

Percentage composition of  Hydrogen peroxide

O = 32/34 = 94.117%

H =    2/34 =   5.882%

3 0
4 years ago
How many uL are present in 250 mL of H20? (1 uL = 10^-6 Liters)​
Vanyuwa [196]

Answer:

250000 μL

Explanation:

If         1 L = 1000 mL

Then  X L = 250 mL

X = (1 × 250) / 1000 = 0.25 L

Now we can calculate the number of microliters (μL) in 0.25 L:

if        1 μL = 10⁻⁶ L

then   X μL = 0.25 L

X = (1 × 0.25) / 10⁻⁶  =250000 μL

4 0
3 years ago
What is the formula mass (molar mass) of sucrose (C12H22O11)?​
Gnesinka [82]
342.3 g/mol

11 times 16
22 times 1
12 times 12
and then add them together
6 0
3 years ago
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