The solubility of potassium chloride in at room temperature is approximately 34 g per 100 g of water. Therefore, the maximum amount that could be dissolved would be 34/100 ( 200) = 68 g of KCl. When more than this amount is added, excess potassium would not dissolve forming crystals in the solution.
Group 17
Please brainliesttt
90 minutes is 1.5 hours.
5 kW * 1.5 hours = 7.5 kWh
8c/kWh * 7.5 kWh = 60 cents
