All categories

2 years ago

HELP ASAP

Chemistry

1 answer:

aksik [14]2 years ago

7 0

Answer:

C: Object 1 is moving, and Object 2 is not moving

Explanation:

Object one has unbalanced forces, so it can cause it to start moving ,since one force is moving stronger than its opposing one, but since Object 2 has balanced forces both forces hold it in place.

You might be interested in

Which describes the dissolving process? (Choose all that Apply)

stich3 [128]

Answer:

A and D

Explanation:

I took the test, and choose both B and C and got it wrong

4 0

2 years ago

What is the mass of 1.2 x 1023 atoms of arsenic?

Gre4nikov [31]

Answer:

14.93 g

Explanation:

First we convert 1.2 x 10²³ atoms of arsenic (As) into moles, using Avogadro's number:

1.2 x 10²³ atoms ÷ 6.023x10²³ atoms/mol = 0.199 mol As

Then we can calculate the mass of 0.199 moles of arsenic, using its molar mass:

0.199 mol * 74.92 g/mol = 14.93 g

Thus, 1.2x10²³ atoms of arsenic weigh 14.93 grams.

6 0

3 years ago

What is the main difference between protrons and neutrons?

m_a_m_a [10]

Answer:

protons are positive and neutrons are neutral, both are in nucleus

Explanation:

5 0

2 years ago

Read 2 more answers

What is the enthalpy of reaction?

erma4kov [3.2K]

Answer:

Enthalpy is the amount of heat released or absorb. The total enthalpy can be found by subtracting the products' enthalpy by the reactants' enthalpy

4 0

2 years ago

Read 2 more answers

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

scoray [572]

Answer:

70.77 g/mol is the molar mass of the unknown gas.

Explanation:

Effusion is defined as rate of change of volume with respect to time.

Rate of Effusion= $\frac{Volume}{Time}$

Effusion rate of oxygen gas after time t = $E=\frac{4.64 mL}{t}$

Molar mass of oxygen gas = M = 32 g/mol

Effusion rate of unknown gas after time t = $E'=\frac{3.12 mL}{t}$

Molar mass of unknown gas = M'

The rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{E}{E'}=\sqrt{\frac{M'}{M}}$

$\frac{\frac{4.64 mL}{t}}{\frac{3.12 mL}{t}}=\sqrt{\frac{M'}{32 g/mol}}$

M' = 70.77 g/mol

70.77 g/mol is the molar mass of the unknown gas.

8 0

3 years ago