Answer:
C₁₁H₁₂NO₄
Explanation:
In order to determine the empirical formula of doxycycline, we need to follow a series of steps.
Step 1: Determine the centesimal composition
C: 59.5 mg/100 mg × 100% = 59.5%
H: 5.40 mg/100 mg × 100% = 5.40%
N: 6.30 mg/100 mg × 100% = 6.30%
O: 28.8 mg/100 mg × 100% = 28.8%
Step 2: Divide each percentage by the atomic mass of the element
C: 59.5 /12.0 = 4.96
H: 5.40/1.00 = 5.40
N: 6.30/14.0 = 0.450
O: 28.8/16.0 = 1.80
Step 3: Divide all the numbers by the smallest one
C: 4.96/0.450 = 11
H: 5.40/0.450 = 12
N: 0.450/0.450 = 1
O: 1.80/0.450 = 4
The empirical formula of doxycycline is C₁₁H₁₂NO₄
You need evidence to support a conclustion
Answer:
The answer to your question is: Molecular formula = C₁₈H₂₄O₂
Explanation:
Estradiol
C = 79.37 %
H = 8.88 %
O = 11.75 %
Molar mass = 272.37
Process
Carbon = 79.37 g
Hydrogen = 8.88 g
Oxygen = 11.75 g
12 g of Carbon ----------------- 1 mol
79.37 g ---------------- x
x = (79.37 x 1) / 12
x = 6.61 mol
1 g of Hydrogen ---------------- 1 mol
8.88 g ---------------- x
x = (8.88 x 1 ) / 1
x = 8.88 mol
16 g of Oxygen ------------------ 1 mol
11.75 g ----------------- x
x = (11.75 x 1) / 16
x = 0.73
Divide by the lowest number of moles
Carbon = 6.61 / 0.72 = 9.2
Hydrogen = 8.88 / 0.73 = 12.2
Oxygen = 0.73/0.73 = 1
Empirical formula
C₉H₁₂O₁
MW of the empirical formula = (12 x 9) + (12 x 1) + (16 x 1)
= 136 g
Divide molar mass of estradiol by the molar mass of the empirical formula.
= 272 / 136
= 2
Then the molecular formula is:
2(C₉H₁₂O) = C₁₈H₂₄O₂
Answer: The temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K
Explanation:
According to ideal gas equation:
P = pressure of gas = 2300 mm Hg = 3.02 atm (760mmHg=1atm)
V = Volume of gas = 15 L
n = number of moles = 0.6
R = gas constant =
T =temperature = ?
Thus the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K