The answer of the matrix equation will be ![\left[\begin{array}{ccc}-2\\3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%5C%5C3%5Cend%7Barray%7D%5Cright%5D)
<h3>What is Matrix ?</h3>
Matrices are known as the tables of numbers. The numbers are usually put into the big brackets. Matrices are given the 'orders', which describes the size of the matrices. The order is the number of rows 'by' the number of columns. For example: a 2 by 3 matrix has 2 rows and 3 columns.
Step-by-step explanation:
1.Find the inverse matrix of the equation
![\left[\begin{array}{ccc}2&1\\1&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%261%5C%5C1%262%5Cend%7Barray%7D%5Cright%5D)
The inverse of this equation will be :
![\left[\begin{array}{ccc}2&-3\\-1&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-3%5C%5C-1%262%5Cend%7Barray%7D%5Cright%5D)
2.Multiply it with ![\left[\begin{array}{ccc}5\\4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C4%5Cend%7Barray%7D%5Cright%5D)
3.Multiply the rows of the first matrix with the columns of another
2×5+(-3)×4
(-1)×5+2×4
4.Simply each element
The answer will be
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Given :-
To Do :-
- To identify slope and y intercept and then sketch it's graph .
Solution :-
Given equation to us is ,
→ y = 3x -1
As we know that , the <u>slope</u><u> </u><u>intercept</u><u> form</u><u> </u> of the line is ,
→ y = mx + c
where m is the slope and c is the y intercept .On comparing both , we have ,
- slope = 3
- y intercept = -1 .
So the graph will cut the y axis at (0,-1) . And will have a slope of 3 .
<u>When </u><u>y </u><u>coordinate</u><u> </u><u>is </u><u>0</u><u> </u><u>,</u>
So that ,
→ x - 0 / 0 -(-1) = 3
→ x/0+1 = 3
→ x/1 = 3
→ x = 3
Hence one other point is (3,0 ).
Now we may plot the graph using these two points (3,0) and (0,-1) .
<u>For</u><u> </u><u>graph</u><u> </u><u>see </u><u>attachment</u><u> </u><u>.</u>
I hope this helps .
I believe the correct answer is true. <span>When solving a system of linear equations, try to algebraically form one equation that has only one variable. In this way, you can solve the value of that variable and eventually solve the other variables. Hope this answers the question. Have a nice day.</span>
Answer:
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