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Naddik [55]
3 years ago
11

Find the difference between the sum of all even numbers and the sum of all odd numbers from 0 through 1000

Mathematics
1 answer:
Anna007 [38]3 years ago
3 0
The sum is 500 because 1000 split betwwen even and odds are even making 500
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Which word completely describes the polygon whose vertices are the ordered pairs (–1, 2), (3, 2), (3, –2), and (–1, –2)?        
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The answer would be "C"
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Bruce weighs 12 pounds less than three times what Dylan weighs. Write an expression for Bruce's weight in terms of Dylan's weigh
skelet666 [1.2K]

Answer:

3d-12=b

Step-by-step explanation:

5 0
3 years ago
Please help me(20 points will give brainliest!!!)
goblinko [34]

Answer:

A. Vertex is ( -1, 16)

B. Do they mean y-intercept for vertical intercept? That is (0,14)

C. X-intercepts are

(-3.838, 0) and (1.828, 0)

Step-by-step explanation:

plug the equation into desmos. It will graph and give you the info.

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6 0
1 year ago
Read 2 more answers
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
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