All categories

3 years ago

A number is not an interger.What type of number can it be?

Mathematics

1 answer:

EleoNora [17]3 years ago

4 0

If it is not an integer, it would have to be a decimal.

You might be interested in

A salesman earns a Commission of $630 for selling $3050 in merchandise

agasfer [191]

Answer:

ok so lets find what percentage 630 is of 3050

630/3050=0.20655737704

so about 20.7%

Hope This Helps!!!

7 0

2 years ago

Plzz i really need this plzz no aubsurd answers

lord [1]

Answer:

Step-by-step explanation:

y= -2x+2

y= -x-3

y= 2/3 x + 1

10.

I'd put a point on (0, 15) , (1, 30), (2, 45) and etc....

Use a ruler to connect these points and use it to draw a straight line that hits all these points.

Good luck

6 0

3 years ago

What is the value of f(x) when x =0

kobusy [5.1K]

Answer:

-1, 2 and 4

Step-by-step explanation:

6 0

3 years ago

Tom wants to drive to his friend's house. If he drives 359 miles a day, how long will it take him to drive 1,462 miles? Round to

agasfer [191]

Answer:

5 days

Step-by-step explanation:

Speed = 359 miles/day

Distance = 1,462 mile

Use this formula to calculate time ( in number of days);

Time = Distance / speed

Next, plug in the numbers given into the formula to calculate time;

Time = 1462 / 359 = 4.0724

Since you are told to round off in days, you will round up 4.0724 to 5 days.

Therefore, it will take Tom 5 days to drive 1,462 miles.

5 0

3 years ago

4. Use the process outlined in the lesson to approximate the number 2√3. Use the approximation √3 ≈ 1.732 050 8.

jeka57 [31]

Answer:

sequence of five intervals

(1) 2 < $2^{\sqrt{3} }$ < $2^{2}$

(2) $2^{1.7}$ < $2^{\sqrt{3} }$ < $2^{1.8}$

(3) $2^{1.73}$ < $2^{\sqrt{3} }$ < $2^{1.74}$

(4) $2^{1.732}$ < $2^{\sqrt{3} }$ < $2^{1.733}$

(5) $2^{1.7320}$ < $2^{\sqrt{3} }$ < $2^{1.7321}$

Step-by-step explanation:

as per question given data

√3 ≈ 1.732 050 8

to find out

sequence of five intervals

solution

as we have given that √3 value that is here

√3 ≈ 1.732 050 8 ........................1

when we find $2^{\sqrt{3} }$ ................2

put here √3 value in equation number 2

we get $2^{\sqrt{3} }$ that is 3.322

sequence of five intervals

(1) 2 < $2^{\sqrt{3} }$ < $2^{2}$

(2) $2^{1.7}$ < $2^{\sqrt{3} }$ < $2^{1.8}$

(3) $2^{1.73}$ < $2^{\sqrt{3} }$ < $2^{1.74}$

(4) $2^{1.732}$ < $2^{\sqrt{3} }$ < $2^{1.733}$

(5) $2^{1.7320}$ < $2^{\sqrt{3} }$ < $2^{1.7321}$

8 0

3 years ago