Answer:
1. 6.37 KJ
2. 3.185 KJ
Explanation:
Gravitational potential energy is a form of potential energy with respect to the force of gravity.
Gravitational potential energy = mass x acceleration due to gravity x height
i.e PE = m x g x h
1. At the top of the platform; mass = 65 kg, acceleration due to gravity = 10 m/, and height = 10 m.
Gravitational potential energy = 65 x 9.8 x 10
= 6370 Joules
The gravitational potential of the diver at the top of the platform is 6.37 KJ.
2. Halfway down; mass = 65 kg, acceleration due to gravity = 10 m/, and height = 5 m.
Gravitational potential energy = 65 x 9.8 x 5
= 3185 Joules
The gravitational potential energy of the diver halfway down is 3.185 KJ.
Answer:
B) +2; 6; -2
Explanation:
In order to know what the coordination number is, all we need to do is to count the number of ligands present in the coordination sphere. Coordination number refers to the number of ligands in the coordination sphere of a given complex. The coordination number here is 6.
The counter ion here is 2Na+. It means that the overall charge on the complex must be -2 because the magnitude of charge on the complex ion is exactly balanced by the number of counter ions.
The charge on the metal (x) must now be;
x + 0 + 4(-1) = -2
x - 4 = -2
x = -2 + 4
x = +2
Note that NH3 is designated as zero because it is a neutral molecule. Each NCS^- ion has a charge magnitude of -1.
Answer:
i dont think so maybe in like 2900 :)
Explanation:
or maybe not i.d.k i don't read the future
Answer:
The vacationer's average density is 912 kg/m³
Explanation:
Archimedes principle states that the buoyancy of an object in a liquid is equal to the weight of the liquid displaced, hence since we have
Density of sea water = 1025 kg/m³
Volume of vocationer's body below water = 89 % of total volume
Mass of seawater displaced = mass of vocationer
volume of seawater displaced = 0.89 × volume of vocationer
volume of vocationer = (volume of seawater displaced)/0.89
Density of vocationer = mass/volume = (mass of seawater displaced)×0.89/(volume of seawater displaced)
Therefore deensity of vocationer = 0.89×density of seawater
= 1025×0.89 = 912 kg/m³
Answer:
true
Explanation:
dunno what a dp is but loves all around.