Balance Chemical Equation is as follow,
<span> Cu + 2 AgNO</span>₃ → 2 Ag + Cu(NO₃)₂
According to Balance Equation,
2 Moles of Ag is produced by reacting = 1 Mole of Cu
So,
0.854 Moles of Ag will be produced by reacting = X Moles of Cu
Solving for X,
X = (0.854 mol × 1 mol) ÷ 2 mol
X = 0.427 Moles of Cu
Result:
0.854 Moles of Ag are produced by reacting 0.427 Moles of Cu.
a) 56g
<h3>Calculation:</h3>
At STP,
22.4 L of N₂ = 1 mol
We have given 44.8 L of N₂, therefore,
44.8 L of N₂ = 
= 
mol
We know that,
1 mol of N₂ = 28 g
Hence,
2 mol of N₂ = 28 × 2
= 56g
Hence, there are 56 g of N₂ in 44.8 L of nitrogen gas.
Learn more about calculation at STP here:
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Answer:
The volume for the ideal gas is: 4647.5 Liters
Explanation:
Formula for the Ideal Gases Law must be applied to solve this question:
P . V = n . R . T
We convert the T° to K → 100°C + 273 = 373 K
We convert pressure value from kPa to atm.
2 kPa . 1atm/101.3 kPa = 0.0197 atm
We replace data in the formula.
V = ( n . R . T) / P → (3 mol . 0.082 . 373K) / 0.0197 atm =
The volume for the ideal gas is: 4647.5 Liters
Gold alloys consist of most commonly Nickel!
Most commonly used in things like jewelry so it doesn't have such a heavy weight.
