The drop down answers are
csc= 1.604
cot= .268
Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0166 = 1.66% probability of a sample proportion of 0.59 or less.
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sampling proportions of a proportion p in a sample of size n has mean
and standard error 
In this problem:
- 1,190 adults were asked, hence

- In fact 62% of all adults favor balancing the budget over cutting taxes, hence
.
The mean and the standard error are given by:


The probability of a sample proportion of 0.59 or less is the <u>p-value of Z when X = 0.59</u>, hence:

By the Central Limit Theorem



has a p-value of 0.0166.
0.0166 = 1.66% probability of a sample proportion of 0.59 or less.
You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213
Answer:
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Step-by-step explanation:
Im not good at math so i use math-way.com
Answer:
The Parry Glitter Company
The Parry Glitter Company should record the Notes Receivable as $300,000.
It should also record the interest receivable per year as $24,000 and the advertising cost as $24,000 per year. These bring into the accounting records the interest revenue and also the advertising expense, which eventually cancel each other.
Step-by-step explanation:
a) Data and Calculations:
Notes Receivable = $300,000
If the notes receivable are repaid at the end of 3 years and it is assumed that the interest on the notes receivable = 8%
Therefore, the cost of the free advertising will be equal to $24,000 ($300,000 * 8%), which is the cost of the interest to the radio station.