The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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For the case of a line through
(
2
,
7
)
and
(
1
,
−
4
)
we have
slope
m
=
Δ
y
Δ
x
=
−
4
−
7
1
−
2
=
−
11
−
1
=
11
Using the point
(
2
,
7
)
we can write the equation of the line in point slope form as:
y
−
7
=
m
(
x
−
2
)
where the slope
m
=
11
.
That is:
y
−
7
=
11
(
x
−
2
)
To get point intercept form, first expand the right hand side so...
y
−
7
=
11
x
−
(
11
⋅
2
)
=
11
x
−
22
Then add
7
to both sides to get:
y
=
11
x
−
15
=
11
x
+
(
−
15
)
This is point intercept (
y
=
m
x
+
c
) form with slope
m
=
11
and intercept
c
=
−
15
.
Answer:
4m - 64
Step-by-step explanation:
Solve 4(m - 16)
4(m - 16) = 4 x m - 16 x 4
= 4m - 64
Answer:
Ox>5
x is less than 5
means nothing more than 5 but anything less than 5
Answer: The height of the flagpole is 12 feet.
Step-by-step explanation:
Let the height of the flagpole be 'H'.
So, from the figure, we can conclude that, the height and shadow of the flagpole is in proportion to the height and shadow of the stick.
Given:
Height of stick is,
Shadow of the stick is,
Shadow of the flagpole is,
Now, as these are in proportion, we have
Plug in the given values and solve for 'H'. This gives,
Hence, the height of the flagpole is 12 feet.
