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3 years ago

Does anyone know this

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

3 0

Answer: you minus the equations you have to get the equation that you want so it all can add up to that *

Step-by-step explanation:

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R−5r−6s+8s−15 what is the answer for this equation

weeeeeb [17]

Step-by-step explanation:

r-5r-6s+8s-15

-4r+2s-15

= 2s-4r-15

4 0

3 years ago

A given field mouse population satisfies the differential equation dp dt = 0.5p − 410 where p is the number of mice and t is the

ohaa [14]

Answer:

a) $t = 2 *ln(\frac{82}{5}) =5.595$

b) $t = 2 *ln(-\frac{820}{p_0 -820})$

c) $p_0 = 820-\frac{820}{e^6}$

Step-by-step explanation:

For this case we have the following differential equation:

$\frac{dp}{dt}=\frac{1}{2} (p-820)$

And if we rewrite the expression we got:

$\frac{dp}{p-820}= \frac{1}{2} dt$

If we integrate both sides we have:

$ln|P-820|= \frac{1}{2}t +c$

Using exponential on both sides we got:

$P= 820 + P_o e^{1/2t}$

Part a

For this case we know that p(0) = 770 so we have this:

$770 = 820 + P_o e^0$

$P_o = -50$

So then our model would be given by:

$P(t) = -50e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=-50 e^{1/2 t} +820$

$\frac{820}{50} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(\frac{82}{5}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(\frac{82}{5}) =5.595$

Part b

For this case we know that p(0) = p0 so we have this:

$p_0 = 820 + P_o e^0$

$P_o = p_0 -820$

So then our model would be given by:

$P(t) = (p_o -820)e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=(p_o -820)e^{1/2 t} +820$

$-\frac{820}{p_0 -820} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(-\frac{820}{p_0 -820}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(-\frac{820}{p_0 -820})$

Part c

For this case we want to find the initial population if we know that the population become extinct in 1 year = 12 months. Using the equation founded on part b we got:

$12 = 2 *ln(\frac{820}{820-p_0})$

$6 = ln (\frac{820}{820-p_0})$

Using exponentials we got:

$e^6 = \frac{820}{820-p_0}$

$(820-p_0) e^6 = 820$

$820-p_0 = \frac{820}{e^6}$

$p_0 = 820-\frac{820}{e^6}$

8 0

3 years ago

Which number has two lines of symmetry?

qaws [65]

I think the answer is d

4 0

3 years ago

Write 3.25 x 10^4 as an ordinary number.

MArishka [77]

Answer:

see below

Step-by-step explanation:

i'm guessing u must be from UK.... in the US "standard form" is known as "Scientific Notation"

Write 3.25 x 10^4 as an ordinary number: 32 500

Write 6.04 x 10^-3 as an ordinary number: 0.00604

Write 2 400 000 in standard form : 2.4 x 10^6

Write 0.00147 in standard form: 1.47 X 10^-3

6 0

3 years ago

Read 2 more answers

Find the expression you can substitute for 5x+y=10

Gennadij [26K]

5x=5*2
Y=0 so 5*2=10 +0 =10

7 0

3 years ago