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3 years ago

Please help me im confused . . . ? ? ? ?

Mathematics

1 answer:

saw5 [17]3 years ago

4 0

its y2-y1 over x2-x1 and you plug in 4 and 8 for x1 and x2 and then 61 and 108 for y1and y2

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Decide if the random variable x, is discrete or continious: x represents the temperature in degrees Fahrenheit on July 4th in Ju

soldi70 [24.7K]

Answer:

Continuous

Step-by-step explanation:

Degrees don't always have to be integers. It can be 32.3 degrees, 32.31 degrees, etc.

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2 years ago

WHAT IS THE RANGE AND DOMAIN. NEED HELP PLEASE.

german

Answer:

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3 years ago

Solve the triangle.<br><br> B = 36°, a = 41, c = 20

svetoff [14.1K]

Answer:

See below

Step-by-step explanation:

When you have 2 sides and the angle between them you use the cosine theorem or law of cosines:

$b^{2}=a^{2}+c^{2}-2acCos(B)$

$b^{2}=41^{2}+20^{2}-2(41)(20)cos36 \\b^{2}=1681 + 400-1327 \\b^{2}=754 \\b = 27.5$

After you have a side and the opposed angle (side b and angle B), you use the law of sines:

$\frac{a}{sinA} =\frac{b}{sinB}=\frac{c}{sinC}$

I will calculate angle A first:

$[tex]\frac{27.5}{sin36} =\frac{41}{sinA} \\sinA =\frac{41}{27.5} sin36 \\sin A = 0.876 \\A = 61.2\°$ [/tex]

Same for angle C:

$\frac{27.5}{sin36} =\frac{20}{sinC} \\sinC =\frac{20}{27.5} sin36 \\sin C = 0.427 \\C = 25.3\°$

The sum of the angles is 36° + 61.2° + 25.3° = 122.5°; The sum must be 180° so this isnt a triangle.

I re did the problem using B as 63° instead of 36° in case you wrote it wrong and I got a satisfactory answer.

using B = 36:

b = 36.6

angle A = 86.4°

angle C = 29.1°

A+B+C = 86.4° + 29.1° + 63° = 178.5° ~ 180°

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3 years ago

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nalin [4]

I’m pretty sure it this if not sorry

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3 years ago

550 tickets were sold for a game for a total of $950.00. If adult tickets sold for $2.00 and children's tickets sold for $1.50,

Naddik [55]

Answer:

244525

hahahahahabasic

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2 years ago