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solmaris [256]
3 years ago
5

A rectangle has an area of 40,if the length and width are doubled. What is the new area ?

Mathematics
2 answers:
MrRissso [65]3 years ago
5 0

160

When you double both the length and width, you are multiplying by 2 twice. Whatever you do to one side of an equation, you have to repeat on the other.

l * w = 40; This is the original equation.

2l * 2w = 40 * 2 * 2; This is when you double the length and the width.

The 2 * 2 on the end can be simplified.

2l * 2w = 40 * 4

Now, simplify 40 * 4.

2l * 2w = 160

So, when you double both the length and the width, you multiply the area by 4, making the area 160.

sweet [91]3 years ago
4 0

Answer:

160

Step-by-step explanation:

e.g. 5×8 --> 10×16 =160

4×10 --> 8×20 =160

2×20 --> 4×40 =160

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Metal Fabrication If an open box is made from a tin sheet 10 in. square by cutting out identical squares from each corner and be
MrRa [10]

Answer:

  • ength (l) : (10-2*5/3) = 20/3
  • width(w): (10 - 2*5/3) = 20/3
  • height(h): 5/3

Step-by-step explanation:

Let x is the side of identical squares

By cutting out identical squares from each corner and bending up the resulting flaps, the dimension are:

  • length (l) : (10-2x)
  • width(w): (10-2x)
  • height(h): x

The volume will be:

V = (10-2x) (10-2x) x

<=> V = (10x-2x^{2}) (10-2x)

<=> V = 100x -20x^{2} - 20x^{2} + 4x^{3}

<=> V = 4x^{3}  - 40x^{2} + 100x

To determine the dimensions of the largest box that can be made, we need to use the derivative and and set it to zero for the maximum volume

dV/dx = 12x^{2} -80x + 100

<=>  12x^{2} -80x + 100 =0

<=> x = 5 or x= 5/3  

You know 'x' cannot be 5 , because if  we cut 5 inch squares out of the original square, the length and the width will be 0. So we take x = 5/3

=>

  • length (l) : (10-2*5/3) = 20/3
  • width(w): (10 - 2*5/3) = 20/3
  • height(h): 5/3
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Step-by-step explanation:

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hope this helps, have a great day :)

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cupoosta [38]
The anwer plus working is 6668/4=151.55
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