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3 years ago

A rectangle has an area of 40,if the length and width are doubled. What is the new area ?

Mathematics

2 answers:

MrRissso [65]3 years ago

5 0

160

When you double both the length and width, you are multiplying by 2 twice. Whatever you do to one side of an equation, you have to repeat on the other.

l * w = 40; This is the original equation.

2l * 2w = 40 * 2 * 2; This is when you double the length and the width.

The 2 * 2 on the end can be simplified.

2l * 2w = 40 * 4

Now, simplify 40 * 4.

2l * 2w = 160

So, when you double both the length and the width, you multiply the area by 4, making the area 160.

sweet [91]3 years ago

4 0

Answer:

160

Step-by-step explanation:

e.g. 5×8 --> 10×16 =160

4×10 --> 8×20 =160

2×20 --> 4×40 =160

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-(-3) is actually -1 * -3 = + 3

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4 years ago

Please help ASAP 40 PTS

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Answer:

Step-by-step explanation:

The angle not marked in the top triangle is 40 degrees since it is an isosceles triangle. That makes the angle opposite it in the other triangle 40 degrees since they are vertical angles and vertical angles are equal.

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Subtract 40 from each side and combine like terms

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Divide by 2

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3 years ago

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Step-by-step explanation:

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2 years ago

Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2

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which follows from the usual change of coordinates via

$\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}$

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$|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|$

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$\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr$

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3 years ago