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3 years ago

How to solve -27/x^15

Mathematics

1 answer:

kompoz [17]3 years ago

8 0

Answer:

$\frac{-27}{x^{15}}=-\frac{27}{x^{15}}$

Step-by-step explanation:

<em>If you just want to simplify -27/x^15, it is not very difficult. Here is the simple way.</em>

<em />

Given the expression

$\frac{-27}{x^{15}}$

solving

$\frac{-27}{x^{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{27}{x^{15}}$

Therefore,

$\frac{-27}{x^{15}}=-\frac{27}{x^{15}}$

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Help please, i need it asap. thank you

Maslowich

Answer:

x = 5

Step-by-step explanation:

$\frac{3}{x}$ = $\frac{4.5}{7.5}$

cross multiply

4.5x = 7.5(3)

4.5x = 22.5

Divide

x = 5

8 0

3 years ago

Question 2 Unsaved Cat is 5 less than twice Dog's age. Cat is 11 years old. Find Dog's age.

madam [21]

Let the dog's age be called x.

From the given statement, the following equation can be framed

Cat's age = 2*x -5

We are given to know that Cat's age is 11 years

So, we have:

11 = 2x -5

2x = 16

x = 16/2

x = 8

Dog's age = 8 years

6 0

3 years ago

Read 2 more answers

Simplify the expression. Write your answer as a power.

jek_recluse [69]

Answer:

(-6.1)^2

Step-by-step explanation:

Look at the attachment

7 0

3 years ago

Need Help ....!!!

postnew [5]

$\\ \sf\longmapsto \dfrac{(0.0225)^{\frac{-3}{2}}\times (0.0001)^{\frac{3}{4}}}{(0.0125)^{\frac{1}{3}}}$

$\\ \sf\longmapsto \dfrac{((0.15)^2)^{\frac{-3}{2}}\times ((0.1)^4)^{\frac{3}{4}}}{(0.5)^3)^{\frac{1}{3}}}$

$\\ \sf\longmapsto \dfrac{(0.15)^{2\times \dfrac{-3}{2}}\times (0.1)^{4\times \dfrac{3}{4}}}{(0.5)^{3\times \dfrac{1}{3}}}$

$\\ \sf\longmapsto \dfrac{(0.15)^{-3}(0.1)^3}{(0.5)^1}$

$\\ \sf\longmapsto \dfrac{\dfrac{1}{(0.15)^3}\times 0.001}{0.5}$

$\\ \sf\longmapsto \dfrac{\dfrac{1}{0.003375}(0.001)}{0.5}$

$\\ \sf\longmapsto\dfrac{ \dfrac{1000000}{3375}\times \dfrac{1}{1000}}{0.5}$

$\\ \sf\longmapsto \dfrac{\dfrac{1000}{3375}}{0.5}$

$\\ \sf\longmapsto \dfrac{1000}{3375}\times \dfrac{10}{5}$

$\\ \sf\longmapsto \dfrac{2000}{3375}$

$\\ \sf\longmapsto 0.592$

4 0

2 years ago

Population Growth Using 20th-century U.S. census data,

asambeis [7]

The population of Ohio will be 10 million in the year 1970

The population growth of Ohio is represented by the function:

$P(t)=\frac{12.79}{1+2.402e^{-}0.0309t}$

P is the population in millions

t is the number of years since 1900

To find the year that the population of Ohio will be 10 million, substitute P = 10 into the function P(t) and solve for t

$10=\frac{12.79}{1+2.402e^{-}0.0309t}\\\\10(1+2.402e^{-}0.0309t)=12.79\\\\1+2.402e^{-}0.0309t=\frac{12.79}{10} \\\\1+2.402e^{-}0.0309t=1.279\\\\2.402e^{-}0.0309t=1.279-1\\\\2.402e^{-}0.0309t = 0.279\\\\e^{-}0.0309t =\frac{0.279}{2.402} \\\\e^{-}0.0309t =0.116\\\\-0.0309t=ln0.116\\\\-0.0309t=-2.154\\\\t=\frac{-2.154}{-0.0309} \\\\t=69.7$

t = 70 years (to the nearest whole number)

70 years after 1900 will be 1970

Therefore, the population of Ohio will be 10 million in the year 1970

Learn more here: brainly.com/question/25504185

5 0

2 years ago