All categories

3 years ago

Find the area of the regular polygon? Please please please the brainiest person help me!!!!!

Mathematics

1 answer:

DaniilM [7]3 years ago

6 0

The area is 162 square root 3

You might be interested in

7.2801098892805 how can i caculate this ASAP PLS

Studentka2010 [4]

Answer:

ja s and the not only way I could

3 0

2 years ago

Please please please helppppppppp

notka56 [123]

Answer:

Step-by-step explanation:

She added 3x and -2x, getting 5x, instead of x. She needs to pay more attention to the positive/negative signs.

6 0

3 years ago

Point (8 5) was translated as follows (8 5) (2.9) A student wrote the algebraic rule to desenbe the translation

MAVERICK [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

3 0

1 year ago

If 2x + 6y = 16, which of the following expressions represents x in terms of y?

Andrej [43]

Answer:

x=-3y+8

Step-by-step explanation:

2x+6y=16

2x=16-6y

2x=-6y+16

x=-6/2y+16/2

x=-3y+8

7 0

3 years ago