First, you have to add 16 to both sides because it's the opposite of subtracting.
h-16<24
+16 +16
-16+16 will cancel each other out.
24+16=40
So, h<40
Or in other words, h is smaller than 40.
Hope it helps ^_^
Answer:
10
Step-by-step explanation:
Area of traingle:1/2
50=1/2.10.x
50=5x
50/5=5x/5
50/5=5x/5
x=50/5
x=10
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer: the value of "x" is 4
The answer is x=-20.
6+ -28 -x =-2
You first add 28 to each side=6+-x=26 then you minus 6 from each side=-x=20.
Then you divide 20 by -x resulting in x=-20
