A bag contain 3 white balls, 4 blue balls and 2 red balls. Two balls are to be taken at random from the bag. The first ball is n
ot replaced before the secod one is taken. Find the probability that
a) the first ball taken will be blue
b) both balls taken will be blue
c) both balls taken will be the same colour
1 answer:
Answer:
a)the first ball taken will be blue
You might be interested in
The answers 15 because we have two negatives it's always a positive and 3×5 is 15
I believe the answer you are looking for is -20.
Answer:
4(4x+3)=19x+9-3x+3
4*4x 4*4 =19x+9-3x+3
16x+12= 16x+12
12=12
I would say 7/24 because when you multiply it you should be able to get a large number.