3t3t3 =9 5t5t5 = 15 add to of the products and get 105
Answer:
12
Step-by-step explanation:
Answer:
The maximum distance is 17.5 miles
No she can't make to the airport.
Step-by-step explanation:
Given the cab charges $0.8 per mile and $2 for tolls.
let the miles travelled by melissa be x.
The total charge is $
Now given that she can spend a maximum of $16
so the inequality is




Therefore the maximum distance she can travel is 17.5 miles
Since the distance to airport is 25 miles which is greater than 17.5 miles she cannot afford the cab.
2/3 of the pie had been eaten, there is 1/3 left
The required Comparison of the inequalities are
- The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.
The range of values encompassing the region's junction is (-13, 15).
- If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.
<h3>What is inequality?</h3>
When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.
We take into account the various variables of the inequality
|x – 1| + 1 > 15
Therefore
|-x-1|+1-1<15-1
|-x-1|-1 <14
13<x<15
The required region lies between the inequality -13 <x< 15.
Simplify the inequality Ix-11+1 > 15 we get,
|x-1|+1 > 15
|x+1| +1-1 >15-1
|x-1| > 14
x> 15
x<-13
- If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
- If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.
Read more about inequalities
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