Step 1:
Calculate the ionic charges on both atoms:
As Strontium belongs to Group-II in periodic table so it will tend to loose two electrons and form Sr⁺² , i.e.
Sr → Sr⁺² + 2 e⁻
While, Se belonging to Group-VI will tend to gain two electrons and form Se⁻², i.e.
Se + 2 e⁻ → Se⁻²
Step 2:
Multiply the coefficient of each element by the charge of other element.
Se⁻² × 2 = 2 Se⁻² ∴ where 2 is charge on Sr
And,
Sr⁺² × 2 = 2 Sr⁺² ∴ where 2 is charge on Se
So, the formula comes out to be,
Sr₂Se₂
Or divide both coefficients by 2 to have a simplest form. i.e...
SrSe
Result:
One One <span>atoms of each element are needed to create an ionic compound of Strontium Selenide.</span>
<span>The balanced chemical ionic equarion of MgS(aq)+CuCl2(aq) = CuS(s)+MgCl2(aq) would be as follows:
</span><span>Mg2+ + S2- + Cu 2+ + 2 Cl- ==> CuS + Mg2+ + 2 Cl-
Therefore, the net equation would be:
</span><span>Cu 2+ + S 2- ===> CuS
</span><span>
Hope this helps.
</span>
Answer:
K2CO3 + 2Na
Explanation:
The equation for the reaction is given below:
Na2CO3 + K —>
Since K is higher than Na in the activity series, K will displace Na and the reaction will proceed as follow:
Na2CO3 + 2K —> K2CO3 + 2Na
The products are K2CO3 + 2Na
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Answer:
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