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Alex17521 [72]
3 years ago
6

A sample of V weighs 61.9 grams. Will a sample of He that contains the same number of atoms weigh more or less than 61.9 grams

Chemistry
1 answer:
damaskus [11]3 years ago
6 0

Answer:

Weigh less than 61.9 g

Explanation:

The symbol V represents the element Vanadium and He represents Helium.

Generally, 1 mol of any atom contains 6.022 * 10^23 atoms. This means we have to find the number of moles of each elements.

For V;

Number of moles = Mass / Molar mass = 61.9 / 50.94 = 1.215 mol

1 mol = 6.022 * 10^23 atoms

1.215 = x

Number of atoms = 6.022 * 10^23 * 1.215 =7.317 * 10^23

For He;

Since equal number of moles contain equal number of atoms;

Number of mol of He = 1.215 mol

Number of moles = Mass / Molar mass

Mass = Molar mass * Number of moles = 4 * 1.215 = 4.86 g

This means it would weigh less.

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<u>Answer:</u> The final equation has hydroxide ions which indicate that the reaction has occurred in a basic medium.

<u>Explanation:</u>

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously.

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.

The given redox reaction follows:

MnO_4^-(aq)+NO_2^-(aq)\rightarrow MnO_2(s)+NO_3^-(aq)

To balance the given redox reaction in basic medium, there are few steps to be followed:

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Oxidation half-reaction: NO_2^-+2OH^-\rightarrow NO_3^-+H_2O+2e^-

Reduction half-reaction: MnO_4^-+2H_2O+3e^-\rightarrow MnO_2+4OH^-

  • Multiply each half-reaction by the correct number in order to balance charges for the two half-reactions

Oxidation half-reaction: NO_2^-+2OH^-\rightarrow NO_3^-+H_2O+2e^-         ( × 3)

Reduction half-reaction: MnO_4^-+2H_2O+3e^-\rightarrow MnO_2+4OH^-             ( × 2)

The half-reactions now become:

Oxidation half-reaction: 3NO_2^-+6OH^-\rightarrow 3NO_3^-+3H_2O+6e^-

Reduction half-reaction: 2MnO_4^-+4H_2O+3e^-\rightarrow 2MnO_2+8OH^-

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Overall redox reaction: 3NO_2^-+2MnO_4^-+H_2O\rightarrow 3NO_3^-+2MnO_2+2OH^-

As we can see that in the overall redox reaction, hydroxide ions are released in the solution. Thus, making it a basic solution

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Mars2501 [29]
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Explanation:

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The correct answer is pentane.

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