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Igoryamba
3 years ago
7

Round 3.255 to the nearest hundredth.

Mathematics
1 answer:
Oduvanchick [21]3 years ago
3 0

Answer:

3.26

Step-by-step explanation:

if there is a five you round it up too 3.26

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Simplify and solve for the unknown. Use order of operations as needed. Check your work.
antiseptic1488 [7]

Answer:

5

Step-by-step explanation:

Given: 5^3– 10^2 = X(8 – 2) + 2X – 3X

Solving the equation to find the value of x.

⇒ 5^{3} -10^{2} = x(8-2)+2x-3x

Using the distributive property of multiplication, multiplying x with 8 and -2

⇒125-100= 8x-2x+2x-3x

cancelling out -2x and 2x

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⇒ 25= 5x

Multiplying both side by 5

⇒ x= \frac{25}{5}

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Hence, the value of unknown is 5.

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When will the equation p(b)=520(0.88)^b have a value less than 100?
yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × 0.88^{b} to have a value less than 100 we can establish inequality as:

                     p(b) < 100

         or,  520 × 0.88^{b} < 100

         or, \frac{520}{520} × 0.88^{b} < \frac{100}{520}

         or, 0.88^{b} < \frac{1}{5.2}

         or, ㏒ ( 0.88^{b} ) < ㏒  (\frac{1}{5.2})

         or, b× ㏒ 0.88 < ㏒  (\frac{1}{5.2})

         or,  \frac{log (\frac{1}{5.2}) }{log (0.88)}   <  b

         or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

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