Answer:
New location at time 3.01 is given by: (7.49, 2.11)
Explanation:
Let's start by understanding what is the particle's velocity (in component form) in that velocity field at time 3:

With such velocities in the x direction and in the y-direction respectively, we can find the displacement in x and y at a time 0.01 units later by using the formula:


Therefore, adding these displacements in component form to the original particle's position, we get:
New position: (7 + 0.49, 2 + 0.11) = (7.49, 2.11)
Answer:
v=0.04m/s
Explanation:
To solve this problem we have to take into account the expression

where v and r are the magnitudes of the velocity and position vectors.
By calculating the magnitude of r and replacing w=0.02rad/s in the formula we have that

the maximum relative velocity is 0.04m/s
hope this helps!!
"Frequency" is a measure of how frequent something is.
Its unit is the "Hertz".
1 Hertz = 1 per second
Answer:
can i have the toy car after your done asking questions with it
Explanation:
The strong force is the only force that can overcome the repulsion between two <span>positively charged nuclei and bind them together.</span>