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kolbaska11 [484]
3 years ago
15

Consider a telescope with a small circular aperture of diameter 2.0 centimeters. Calculate the angular separation θ1 at which tw

o point sources of wavelength 600 nanometers are just resolved when viewed through a circular aperture of diameter 1.5 centimeters.
Physics
1 answer:
kogti [31]3 years ago
7 0

To solve this problem it is necessary to apply the concepts related to diffraction through a circular opening.

By definition the angular resolution is given by

\theta = 1.22\frac{\lambda}{D}

Where,

\lambda = Wavelenght

D = Diameter of the lens aperture.

Our values are given as,

\lambda = 600*10^{-9}m

d = 1.5*10^{-2}m

Therefore replacing,

\theta = 1.22\frac{600*10^{-9}}{1.5*10^{-2}}

\theta = 4.88*10^{-5} rad

Therefore the angular separation is 4.88*10^{-5} rad

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If a woman needs an amplification of 1.0 ✕ 105 times the threshold intensity to enable her to hear at all frequencies, what is h
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Answer:

50 dB.

Explanation:

given,

Amplification needed by the woman,I= 1 x 10⁵ I₀

where as I₀ is the threshold frequency

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Using the equation of sound intensity level

\beta(dB) = 10 log(\dfrac{I}{I_0})

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7 0
4 years ago
In the 1980s, the term picowave was used to describe food irradiation in order to overcome public resistance by playing on the w
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Answer:

E = 1.24MeV

Explanation:

The photon travels at the speed of light, 3.0 × 10^{8} m/s, and given that its frequency = 1 picometer = 1.0 × 10^{-12} m.

Its energy can be determined by;

E = hf

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where E is the energy, h is the Planck's constant, 6.626 × 10^{-34} Js, c is the speed of the light and f is its frequency.

Therefore,

E = (6.626 × 10^{-34}× 3.0 × 10^{8}) ÷ 1.0 × 10^{-12}

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E = 1.9878 × 10^{-13} J

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E = \frac{1.9878*10^{-13} }{1.6*10^{-19} }

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The energy of the photon is 1.24MeV.

5 0
3 years ago
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