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SCORPION-xisa [38]
3 years ago
13

It would take 38 minutes to fall through a (hypothetical) hole from one end of the Earth to the other. Until recently, it was th

ought to be 42 minutes. What is the percent change in the "hypothetical" time it takes
Physics
1 answer:
QveST [7]3 years ago
4 0

Answer:

The percentage change in the hypothetical time is 10.53%

Explanation:

Percentage change in a quantity is given by;

\frac{Final quantity - Initial quantity}{Initial quantity} * 100%

In this case, the quantity in question is time.

Therefore, percentage change in time =

\frac{Final time- Initial time}{Initial time} * 100%

<em>where;</em>

Final time = 42minutes

Initial time = 38minutes

Substituting these values into the equation above gives;

=> \frac{42 - 38}{38} * 100%

=> \frac{4}{38} * 100%

=> 10.53%

<em>Hope this helps!</em>

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Where would sound NOT be
Tcecarenko [31]
The answer is D, or Outer Space.

Explanation:

Sound is implemented through mechanical wave transferral, which requires a medium (solid, liquid, or gas) to travel through. Because sound is a mechanical wave, it cannot travel through vacuums (space).
6 0
3 years ago
A flock of ducks is trying to migrate south for the winter, but they keep being blown off course by a wind blowing from the west
Minchanka [31]

The ducks' flight path as observed by someone standing on the ground is the sum of the wind velocity and the ducks' velocity relative to the wind:

ducks (relative to wind) + wind (relative to Earth) = ducks (relative to Earth)

or equivalently,

\vec v_{D/W}+\vec v_{W/E}=\vec v_{D/E}

(see the attached graphic)

We have

  • ducks (relative to wind) = 7.0 m/s in some direction <em>θ</em> relative to the positive horizontal direction, or

\vec v_{D/W}=\left(7.0\dfrac{\rm m}{\rm s}\right)(\cos\theta\,\vec\imath+\sin\theta\,\vec\jmath)

  • wind (relative to Earth) = 5.0 m/s due East, or

\vec v_{W/E}=\left(5.0\dfrac{\rm m}{\rm s}\right)(\cos0^\circ\,\vec\imath+\sin0^\circ\,\vec\jmath)

  • ducks (relative to earth) = some speed <em>v</em> due South, or

\vec v_{D/E}=v(\cos270^\circ\,\vec\imath+\sin270^\circ\,\vec\jmath)

Then by setting components equal, we have

\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta+5.0\dfrac{\rm m}{\rm s}=0

\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v

We only care about the direction for this question, which we get from the first equation:

\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta=-5.0\dfrac{\rm m}{\rm s}

\cos\theta=-\dfrac57

\theta=\cos^{-1}\left(-\dfrac57\right)\text{ OR }\theta=360^\circ-\cos^{-1}\left(-\dfrac57\right)

or approximately 136º or 224º.

Only one of these directions must be correct. Choosing between them is a matter of picking the one that satisfies <em>both</em> equations. We want

\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v

which means <em>θ</em> must be between 180º and 360º (since angles in this range have negative sine).

So the ducks must fly (relative to the air) in a direction 224º relative to the positive horizontal direction, or about 44º South of West.

8 0
3 years ago
What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?Use 1.67×
vazorg [7]

The electric force on the proton is:

F = Eq

F = electric force, E = electric field strength, q = proton charge

The gravitational force on the proton is:

F = mg

F = gravitational force, m = proton mass, g = gravitational acceleration

Since the electric force and gravitational force balance each other out, set their magnitudes equal to each other:

Eq = mg

Given values:

q = 1.60×10⁻¹⁹C, m = 1.67×10⁻²⁷kg, g = 9.81m/s²

Plug in and solve for E:

E(1.60×10⁻¹⁹) = 1.67×10⁻²⁷(9.81)

E = 1.02×10⁻⁷N/C

5 0
3 years ago
If an object with constant mass is accelerating, what does Newton's second
aliina [53]

Answer:

C. A force must be acting on the object.

Explanation:

This is due to the action of its momentum direction.

.

6 0
3 years ago
2. What is the kinetic energy of a 7.26 kg bowling ball that is rolling at a speed of 2 m/s?
telo118 [61]

Kinetic energy is the energy possessed by an object when that object is moving in space. The higher the mass of an object or higher the speed of an object the higher the kinetic energy will be.

So to calculate the Kinetic Energy we can use the following formula

K.E=(1/2)*m*v^2

Inserting the values in formula gives:

K.E=1/2*7.26*2^2

14.52J

This is the final answer which gives the kinetic energy of the ball.

6 0
3 years ago
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