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VMariaS [17]
3 years ago
8

If the net force on an object is zero, then the object has

Physics
2 answers:
Nonamiya [84]3 years ago
7 0

Answer:

Balanced Forces :D

Explanation:

Lyrx [107]3 years ago
5 0
The answer is B !!!! Balanced forces
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satela [25.4K]

Answer:

use this formula

Average Speed = (Total distance)/(Total Time) =

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Question 10 (5 points)
Anastaziya [24]

Answer:

A. it will move faster than the large object was moving initially

8 0
4 years ago
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Add the following vectors using head-to-tail method and verify your results using the component method.
Oxana [17]

Answer:

See attached image for the requested graphs.

Part 1 : Vector sum is about 9.4 cm long in the graph, from components: about 9.35 cm long. Percent difference = 0.5%

Part 2: Vector sum is about 7.6 cm long in the graph and from components: 7.57 cm long. Percent difference = 0.4%

Explanation:

Part 1.

The graphical addition of the three vectors A, B and C gives a vector sum of approximately 9.4 cm at an angle of about 84 degrees

The component form addition is

Ax + Bx + Cx  = 3.5 + 0 + (-2.5)  = 1

Ay + By + Cy  = 2.0 + 3 + 4.3  = 9.3

Magnitude: \sqrt{1^2+9.3^2} \approx 9.35\,\,cm

The percent difference is: (9.4-9.35) * 100 /9.35 = 0.5%

Part 2.

The graphical addition of the four vectors (A, B, C, and D) measures approximately  7.6 cm at an angle of about 124 degrees.

The component form addition is

Ax + Bx + Cx + Dx = 3.5 + 0 + (-2.5) + (-5.2) = -4.2

Ay + By + Cy + Dy = 2.0 + 3 + 4.3 + (-3) = 6.3

Magnitude = \sqrt{(-4.2)^2+6.3^2} \approx 7.57\,\,cm

The percent difference is: (7.6-7.57) * 100 /7.57 = 0.4%

6 0
3 years ago
Using energy considerations, calculate the average force (in N) a 62.0 kg sprinter exerts backward on the track to accelerate fr
slava [35]

Answer:

69.68 N

Explanation:

Work done is equal to change in kinetic energy

W = ΔK = Kf - Ki = \frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

W = F_{total} .d

where m = mass of the sprinter

vf = final velocity

vi = initial velocity

W  = workdone

kf = final kinetic energy

ki = initial kinetic energy

d = distance traveled

Ftotal = total force

vf = 8m/s

vi= 2m/s

d = 25m

m = 60kg

inserting parameters to get:

W = ΔK = Kf - Ki = \frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

F_{total} .d =\frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

F_{total} = \frac{\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}}{d}

F_{total=} \frac{\frac{1}{2} X 62 X6^{2} -\frac{1}{2} X 62 X2^{2} }{25}

= 39.7

we know that the force the sprinter exerted F sprinter, the force of the headwind Fwind = 30N

F_{sprinter} = F_{total} + F_{wind}  = 39.7 + 30 = 69.68 N

7 0
3 years ago
Read 2 more answers
A gyroscope flywheel of radius 1.96 cm is accelerated from rest at 13.0 rad/s2 until its angular speed is 2270 rev/min. (a) What
nika2105 [10]

Tangential acceleration of a point on the rim of the flywheel during this spin-up process is 0.2548 m/s².

Tangential acceleration is defined as the rate of change of tangential velocity of the matter in the circular path.

Given,

Radius of flywheel (r) = 1.96 cm = 0.0196m

Angular acceleration (α)= 13.0 rad/s²

The tangential acceleration formula is at=rα

where, α is the angular acceleration, and r is the radius of the circle.

using the formula; at=rα  = (13.0 rad/s²) (0.0196m) = 0.2548 m/s².

The tangential acceleration is 0.2548 m/s².

Learn more about the Tangential acceleration with the help of the following link:

brainly.com/question/15743294

#SPJ4

5 0
2 years ago
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