A gyroscope flywheel of radius 1.96 cm is accelerated from rest at 13.0 rad/s2 until its angular speed is 2270 rev/min. (a) What
1 answer:
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We use the kinematic equations,
(A)
(B)
Here, u is initial velocity, v is final velocity, a is acceleration and t is time.
Given, ,
and
.
Substituting these values in equation (B), we get
.
Therefore from equation (A),
Thus, the magnitude of the boat's final velocity is 10.84 m/s and the time taken by boat to travel the distance 280 m is 51.63 s
Answer:
0.04328 H
0.00288 seconds
0.01326 seconds
Explanation:
V = Voltage = 6.3 V
R = Resistance = 15 Ω
L = Inductance
I = Decayed current = 0.21 A
t = Time to decay = 2 ms
Maximum Current is given by
Current in the circuit is given by
The inductance is 0.04328 H
Time constant is given by
Time constant is 0.00288 seconds
Time required is given by
The time to reach 1% of its original value is 0.01326 seconds
Answer:
C. 0.2 Hertz
Explanation:
The frequency of a spring is equal to the reciprocal of the period:
where
f is the frequency
T is the period
For the spring in this problem,
T = 5 s
therefore, the frequency is