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AlexFokin [52]
3 years ago
7

All 3000 seats in the theater are being replaced.So far 5 sections of 136 seats have been replaced. How many more seats do they

still need to replace?
Mathematics
1 answer:
kondor19780726 [428]3 years ago
4 0


you would have 2320 seat left.

136 x 5 = 680      3000 - 680 = 2320

you have to do 136 x 5 because there are 136 seats in each section.


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Juli2301 [7.4K]

Answer/Step-by-step explanation:

The equation of the line that passes through the two points would be correct if each point, when substituted into the equation, satisfy the equation.

This is what I mean:

Given the equation of the line, y = 2x - 5, and the two points (-2, -9) and (3, 1):

For the first point, substitute x = -2, and y = -9 into y = 2x - 5.

Thus:

-9 = 2(-2) - 5

-9 = -4 - 5

-9 = -9 (this is true). It means the line runs through the point (-2, -9)

For the second point, substitute x = 3, and y = 1 into y = 2x - 5

This:

1 = 2(3) - 5

1 = 6 - 5

1 = 1 (this is true). This also means the point, (3, 1) is also a point that the equation runs across.

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2 years ago
What is the shaded portion of the circle
blagie [28]

Answer:

(5\pi-11.6)\ ft^{2}

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the sector minus the area of the triangle

step 1

Find the area of the circle

the area of the circle is equal to

A=\pi r^{2}

we have

r=5\ ft

substitute

A=\pi (5)^{2}

A=25\pi\ ft^{2}

step 2

Find the area of the sector

we know that

The area of the circle subtends a central angle of 360 degrees

so

by proportion find out the area of a sector by a central angle of 72 degrees

\frac{25\pi}{360}=\frac{x}{72}\\ \\x=72*25\pi /360\\ \\x=5\pi\ ft^{2}

step 3

Find the area of triangle

The area of the triangle is equal to

A=\frac{1}{2}(2.9+2.9)(4)= 11.6\ ft^{2}

step 4

Find the area of the shaded region

Subtract the area of the triangle from the area of the sector

(5\pi-11.6)\ ft^{2}

8 0
2 years ago
A gallon of paint is used to paint a room. One third of the paint is used on the first day. On the second day, one third of the
irga5000 [103]
1/3 of remained 2/3 is 2/9. We’ve used 1/3+2/9 = 3/9+2/9 = 5/9. So we’ve used 5/9 and we have 4/9 of the paint
6 0
3 years ago
Read 2 more answers
Find the coordinates of the other endpoint of the​ segment, given its midpoint and one endpoint.​ (Hint: Let​ (x,y) be the unkno
makkiz [27]

Step-by-step explanation:

Hey, there!!

Here, one point is A(10,8) and P(8,5) is the midpoint.

Let B(x,y) be the another end point.

Now,

Using midpoint formulae,

p(x.y) =  \frac{x1 + x2}{2} . \frac{y1 + y2}{2}

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Since they are equal,equating with their corresponding elements we get,

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Therefore, x = 6

Now,

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or, 10 = 8 + y

or, y = 2

Therefore, The coordinates of another point are B(6,2)

<em><u>Hope it helps</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Determine the nature of the roots:
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Answer:

A.  2 distinct roots.

Step-by-step explanation:

2x^2 + 8x + 3 = 0

Finding the discriminant:

b^2 - 4ac = 8^2 - 4 * 2 * 3

=  64 - 24

= 40

The discriminant is positive but not a perfect square

So there are 2 distinct ,real, irrational roots.

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2 years ago
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